3RD ITERATION: x₂ = 3-X₂ +2₂ 3-1 + 1.1875 = 1.0625 3 3 Yo= 7-2x₂₁-22-7-2 10.757-1-1875 4 4 1.078125 F 23 = 4-X₂+x₂ - 4 - (0-75) +1 H = 1.0625 4 9 Iteration Y O 1 2 O Z 5 decimal O O 1 1.75 1 0.75 1 1-1875 3 1.0625 1-078125 1.0625 4 0.994792 0.953125) 1-003906 S 1.016927 1.001628 0-989583 6 0-995985 0.994141 0.996175 0.999539 1-000678 1.00303 As required, the difference of the last iteration Should be less than 0.005, X=1; y = 1 ; 2=
3RD ITERATION: x₂ = 3-X₂ +2₂ 3-1 + 1.1875 = 1.0625 3 3 Yo= 7-2x₂₁-22-7-2 10.757-1-1875 4 4 1.078125 F 23 = 4-X₂+x₂ - 4 - (0-75) +1 H = 1.0625 4 9 Iteration Y O 1 2 O Z 5 decimal O O 1 1.75 1 0.75 1 1-1875 3 1.0625 1-078125 1.0625 4 0.994792 0.953125) 1-003906 S 1.016927 1.001628 0-989583 6 0-995985 0.994141 0.996175 0.999539 1-000678 1.00303 As required, the difference of the last iteration Should be less than 0.005, X=1; y = 1 ; 2=
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
ChapterP: Prerequisites
SectionP.FOM: Focus On Modeling: Making The Best Decisions
Problem 6P
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Solve the given system of linear equations using the Jacobi Method . The answer should have atleast 5 decimal places. Box thw final answer.
1.) 3x1 - x2 + x3 = 2
2x1 - 3x2 - x3 = 7
3x1 - x2 + 4x3 = 5
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