3y CC) (2x)*(3y)"-i = Зу - (2х + 3у)" 2x n n E)(2x)-'(3y)"-i+1 %3D %3D 2x i=0 i=0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 41E
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Can you explain this step by step please. 

How did it go from (2x)i-1 (3y)n-i+1 to (2x + 3y)n

n
3y
3y
i-1
-i+1
- (2х + 3у)"
2x
n-i
2x
i=0
i=0
Transcribed Image Text:n 3y 3y i-1 -i+1 - (2х + 3у)" 2x n-i 2x i=0 i=0
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