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4 3 2 a. f(x) = log(x) b. f(x) = log(x) - c. f(x) = -log₁(x) 2 d. f(x) = log(x) 1 -5-4-3-2-1 1 2 3 4 5 -1 -2 -34 -4 -5 5 4 3 2 1 -5-4-3-2-1 2 3 5 -1 -2 -3 -4 -5- 5 4- 3 2 1 -5-4-3-2-1 < 3 5 -1 -2 -3 -4 -5- 5 4 3 2 1 -5 -4 -3 -2 -1 2 3 4 5 -1 -2

4 3 2 a. f(x) = log(x) b. f(x) = log(x) - c. f(x) = -log₁(x) 2 d. f(x) = log(x) 1 -5-4-3-2-1 1 2 3 4 5 -1 -2 -34 -4 -5 5 4 3 2 1 -5-4-3-2-1 2 3 5 -1 -2 -3 -4 -5- 5 4- 3 2 1 -5-4-3-2-1 < 3 5 -1 -2 -3 -4 -5- 5 4 3 2 1 -5 -4 -3 -2 -1 2 3 4 5 -1 -2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.4: Logarithmic Functions
Problem 7E
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4 3 2 a. f(x) = log(x) b. f(x) = log(x) - c. f(x) = -log₁(x) 2 d. f(x) = log(x) 1 -5-4-3-2-1 1 2 3 4 5 -1 -2 -34 -4 -5 5 4 3 2 1 -5-4-3-2-1 2 3 5 -1 -2 -3 -4 -5- 5 4- 3 2 1 -5-4-3-2-1 < 3 5 -1 -2 -3 -4 -5- 5 4 3 2 1 -5 -4 -3 -2 -1 2 3 4 5 -1 -2
Transcribed Image Text:4 3 2 a. f(x) = log(x) b. f(x) = log(x) - c. f(x) = -log₁(x) 2 d. f(x) = log(x) 1 -5-4-3-2-1 1 2 3 4 5 -1 -2 -34 -4 -5 5 4 3 2 1 -5-4-3-2-1 2 3 5 -1 -2 -3 -4 -5- 5 4- 3 2 1 -5-4-3-2-1 < 3 5 -1 -2 -3 -4 -5- 5 4 3 2 1 -5 -4 -3 -2 -1 2 3 4 5 -1 -2
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