4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K¡ =2 and K2 = 4. Parallel-plates have the area A = 0.8 m². The distance is d= 0.2 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m?) %3D A K2 A K1 HHE А AV1 AV = 24 V

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4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric
constants are K = 2 and K, = 4. Parallel-plates have the area A = 0.8 m². The distance is d = 0.2 m.
A potential difference of AV = 24 V is applied to the circuit.
(a) Find the equivalent capacitance of the system.
(b) Find the potential AV,. (E,=8.85×10-12 C²/N×m²)
d
A
K2
d
А
K1
d
`A
А
AV1
AV = 24 V
Transcribed Image Text:4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K = 2 and K, = 4. Parallel-plates have the area A = 0.8 m². The distance is d = 0.2 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV,. (E,=8.85×10-12 C²/N×m²) d A K2 d А K1 d `A А AV1 AV = 24 V
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