4 in. 2 in. A | VA = (VA)xi + (VA)yj B 2 in. VB = (VB)xi + (VB) yj 6 in.- Vc = (Vc)xi + (Vc)yj C X
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The plate shown moves in the xy plane. Know that (vA)x = 12 in./s, (vB)x = –4 in./s, and (vC)y = –23 in./s.
a)Determine the angular velocity of the plate.
b)Determine the velocity of point B. (i j)
c)Determine the point of the plate with zero velocity. (x,y)
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- J 5: !!!Please show it mathematically, not theoryFor the system below, EI is constant. If x = 6.73 m from point B, determine the value of EI(Δ) ? If x = 2.49 m from point B, determine the value of EI(θ) ? If x = 7.57 m from point B, determine the value of EI(Δ) ? If x = 4.79 m from point B, determine the value of EI(θ) ?A point M is 20mm above HP and 18mm in front of VP. Another point N is 45mm above HP and 25mm in front of VP. If the gap between Mo and No is 40mm then draw and find the gap between the front views and top views of both the points.
- PLS TAKE VÆ = 1+2=3ᴀ ꜱᴏʟɪᴅ ꜱʜᴀꜰᴛ 2.51" ɪɴ ᴅɪᴀᴍᴇᴛᴇʀ ᴛʀᴀɴꜱᴍɪᴛꜱ ᴀɴ ᴀʟᴍᴏꜱᴛ ᴄᴏɴꜱᴛᴀɴᴛ ᴘᴏᴡᴇʀ ᴏꜰ 100 ʜᴘ ᴀᴛ ᴀ ᴄᴏɴᴛɪɴᴜᴏᴜꜱʟʏ ᴠᴀʀʏɪɴɢ ꜱᴘᴇᴇᴅ ᴏꜰ 100 ᴛᴏ 500 ʀᴘᴍ. ᴄᴏᴍᴘᴜᴛᴇ ᴛʜᴇ ᴍᴇᴀɴ ꜱᴛʀᴇꜱꜱ ᴄᴏᴍᴘᴏɴᴇɴᴛ (SMs) ᴏꜰ ᴛʜᴇ ꜱʜᴀꜰᴛ ɪɴ ᴘꜱɪ. ᴇxᴘʀᴇꜱꜱ ʏᴏᴜʀ ᴀɴꜱᴡᴇʀ ᴜꜱɪɴɢ 4 ꜱɪɢɴɪꜰɪᴄᴀɴᴛ ꜰɪɢᴜʀᴇꜱ. ʀᴏᴜɴᴅ ʏᴏᴜʀ ᴀɴꜱᴡᴇʀ ᴛᴏ 4 ꜱɪɢɴɪꜰɪᴄᴀɴᴛ ꜰɪɢᴜʀᴇꜱ.Her foot pivots as a single structure about a single pivot in her ankle. When she stands on tiptoe, her foot pivots about her ankle. As shown in the foot diagram and the free-body diagram below, the forces on one foot are an upward force on her toes from the floor, a downward force on her ankle from the lower leg bone (called the Tibia), and an upward force on the heel of her foot from her Achilles Tendon. Suppose a 61.3 kg woman stands on one foot, on tiptoe, with the sole of her foot making a 25.0 degree angle with the floor, and with the distances are as shown in the figure.
- Solve for Problem 2, when RN1 = 0145A line RS of 55 mm in length is inclined to HP by 30o and parallel to VP. One of its end points is above HP by 20 mm and in front of VP by 30 mm. The line is in single quadrant. Find the projections of the line RS and find out its horizontal trace.Distributed load, w0 = 4 N/mL = 3.4 m Find the following: Find the magnitude of the equivalent concentrated force (in N). Find the distance of the equivalent concentrated force from A (in m).
- Given the figure before, when the displacement of block D is 360 ft, then the displacement of block A is closest to:-Drawing the relationship between the linear displacement (x) and the angle (theta) in practice through the readings you want. The device then unifies the slope at different points of the rest diagram to practically find the values of the free velocity of the slide and draw the relationship between the linear velocity and the angle (theta), which is a sinusoidal function and be a cosine function. Note:-r=25 mm, l=150 mm.TRUE OR FALSE. SHOW SOLUTION. 47 lb-in is equivalent to 4.31 N-m.