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4 m2 m2 mBAmA m60°m200 KN60°"Fig P4.180Fig. P4.1814.181 Determine the ratio PIQ for which the parallel linkage will be inequilibrium in the position shown. Neglect the weights of the members

Question
4 m
2 m
2 m
B
A
m
A m
60°
m
200 KN
60°
"Fig P4.180
Fig. P4.181
4.181 Determine the ratio PIQ for which the parallel linkage will be in
equilibrium in the position shown. Neglect the weights of the members
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4 m 2 m 2 m B A m A m 60° m 200 KN 60° "Fig P4.180 Fig. P4.181 4.181 Determine the ratio PIQ for which the parallel linkage will be in equilibrium in the position shown. Neglect the weights of the members

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Step 1

Given information:

Given the member is

2m
2m
с
в
60
60°
А
4 m
2 m
4 m
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2m 2m с в 60 60° А 4 m 2 m 4 m

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Step 2

Calculation:

Draw the free body diagram for the beam,

2m
2m
В
60°
60°
DX
Ax
DY
Ay
4 m
2m
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2m 2m В 60° 60° DX Ax DY Ay 4 m 2m

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Step 3

From this free body diagram we can get the reactions of A and D. Those are Ax, Ay...

ΣΜ,-0
D, (4)-P(4 cos 60+2)+Q(6sin 60) = 0
D,(4) P(4cos 60+2)-Q(6 sin 60)
P(4 cos 60+2)
(6sin 60)
-Q
Dy
Dr P-1.29. )
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ΣΜ,-0 D, (4)-P(4 cos 60+2)+Q(6sin 60) = 0 D,(4) P(4cos 60+2)-Q(6 sin 60) P(4 cos 60+2) (6sin 60) -Q Dy Dr P-1.29. )

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