4) xy dx + (y + 1)e¬*dy = 0 Ans: (x – 1)e* =-+ + c (Xie, 2010)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Test Yourself 02
Obtain the required solution based on the given equation and condition (if there's any).
1) 4xdy – ydx = x?dy Ans: (x – 4)y4 = cx (Ayres, Differential Equations, 1952)
2) sec?x tan y dy + sec²y tan x dx = 0 Ans: cos 2x + cos 2y = c (Bali, 2007)
3) yv1+ x²dx +x/1+y?dy = 0
Ans:
V1+ x² +/1+ y² =
%3D
(1+v1+x?)(1+V1+y²)
In
+ c (Bali, 2007)
xy
4) xy³dx + (y + 1)e¬*dy = 0 Ans: (x – 1)e* = - ++ c (Xie, 2010)
y
2y2
Transcribed Image Text:Test Yourself 02 Obtain the required solution based on the given equation and condition (if there's any). 1) 4xdy – ydx = x?dy Ans: (x – 4)y4 = cx (Ayres, Differential Equations, 1952) 2) sec?x tan y dy + sec²y tan x dx = 0 Ans: cos 2x + cos 2y = c (Bali, 2007) 3) yv1+ x²dx +x/1+y?dy = 0 Ans: V1+ x² +/1+ y² = %3D (1+v1+x?)(1+V1+y²) In + c (Bali, 2007) xy 4) xy³dx + (y + 1)e¬*dy = 0 Ans: (x – 1)e* = - ++ c (Xie, 2010) y 2y2
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