4. At high temperatures, nitrogen dioxide, NO2, decomposes into NO and O2. If y(t) is the concentration of NO2 (in moles per liter), then at 600°K, y(t) changes according to the reaction law = -.05y² for time t in seconds. dt A. Express y in terms of t and the initial concentration y.. B. Assuming that the concentration of NO2 is twice as high at t = 20 seconds as it is at 100 seconds, find the exact initial concentration of the NO2. Reminder: “Exact" means no calculator numbers.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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4. At high temperatures, nitrogen dioxide, NO2, decomposes into NO and O2. If y(t) is the
concentration of NO2 (in moles per liter), then at 600°K, y(t) changes according to the
reaction law dy
-.05y² for time t in seconds.
=
A. Express y in terms of t and the initial concentration y..
B. Assuming that the concentration of NO2 is twice as high at t = 20 seconds as it is at
seconds, find the exact initial concentration of the NO2. Reminder: “Exact" means no
calculator numbers.
Transcribed Image Text:4. At high temperatures, nitrogen dioxide, NO2, decomposes into NO and O2. If y(t) is the concentration of NO2 (in moles per liter), then at 600°K, y(t) changes according to the reaction law dy -.05y² for time t in seconds. = A. Express y in terms of t and the initial concentration y.. B. Assuming that the concentration of NO2 is twice as high at t = 20 seconds as it is at seconds, find the exact initial concentration of the NO2. Reminder: “Exact" means no calculator numbers.
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