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- The admittance for a circuit, G + jB, is 0.02 + j0.20. What is the impedance, R + jX? Provide illustration of the circuit.If i = 4 sin(2*pi*f*t - 30°) and v = 7sin(2*pi*f*t-50degrees) which one of these statements is true? i leads v by 20° i leads v by 80° i lags v by 20° i lags v by 80°Find the admittance YabYab in the circuit seen in the figure. Take that R1 = 5 Ω , 2R = 2Ω , R3 = 7 Ω and R4 = 15 Ω. Pt A. Express Yab in rectangular form.
- Use CTFT table and properties to find the numerical value of x(t) at t=0.75 if x(t)= 3 sinc (2t) * sinc (4t) : Select one: a. 0.75 sinc (1.5) b. None of the given options c. 3 sinc (1.5) + 3 sinc (3) d. 3 sinc (1.5) sinc (3) e. 3/8 rect (1.5) rect (3)A resistor of 100 Ω, a coil of 4.50 uH and a capacitor of 220 pH are in parallel. What is the impedance vector at8.50 MHz?A. 100 + j 240 ohms C. 100 – j 240 ohmsB. 258u + j160.6 m ohms D. 258u - j160.6m ohmsFind the two elements in a series circuit (i.e., R and L, or R and C, or L and C), given that i(t) = 2 √2 sin(120πt + π/6) A. and v(t) = 100 √2 cos(120πt - π/6)
- The voltage and current at the terminals of an ideal basic circuit element are zero for t < 0. For t > or = 0, they are: v = 100e^-50t(sin150t) V i = 20e^-50t(sin150t) A a) Find the power absorbed by the element at t = 20 ms. b) Find the total energy absorbed by the circuit.Use source transformation to determine Vo as a result of the independent contribution from the voltage source Vs=18<90°. Give the answer in rectangular formFor the circuit shown, determine:a) Plot pole-zero diagram for H = I / Vsb) Based on H, calculate the forced response for i (t) to an excitation:Vs (t) = 5 e-3tsin (50t) cos (60t) [V]
- Convert k = (1.55∠–18.7°) to rectangular form, (A + jB) Solve the real and imaginary partHi, i just need some more detail in relation to the answer provided. In step 3 the stated Zlv= 71.853∠26.697° Ω Then in step 4: If = V/Z =24/56.454 How has "Z" changed from 71.853 to 56.454. ThanksEvaluate the following: a) 2 / (1+j) ^4 b) j [ (1+j3) / (1-j2) ] ^2