4. Find the area of the surface formed by revolving the graph of f(x) = x² on the interval [0, √2]about the y-axis, as shown in the figure below. y -2 -1 3 2 r(x) = x Axis of revolution (√2, 2) f(x)=² 2

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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4. Find the area of the surface formed by
revolving the graph of f(x) = x² on
the interval [0, √2]about the y-axis, as
shown in the figure below.
3
2
y
r(x) = x
Axis of revolution
(√2,2)
f(x)=x²
2
I
Transcribed Image Text:4. Find the area of the surface formed by revolving the graph of f(x) = x² on the interval [0, √2]about the y-axis, as shown in the figure below. 3 2 y r(x) = x Axis of revolution (√2,2) f(x)=x² 2 I
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