4. f(x) = eªx (−ï < x < ï), where a ‡ 0. Suggestion: Use Euler's formula eie = Answer: Answer: an + ibn: 5. f(x) = cosh ax (-л < x < л), where a After evaluating this single integral, equate real parts and then imaginary parts. sinh an 2 sinh an + ап TT sinhan ал Answer: - T 0. Suggestion: Use the series found in Problem 4. 8 Σ n=1 1+2a3 Σ Σ - n=1 1 2q² = S 一元 + 8 cos+ i sin 0, where i = √-1, to write [ f(x) einx dx cos ax = (-1)" a²+ n² 6. f(x) = cos ax (-л < x <л), where a 0, ±1, ±2,.... Suggestion: With the aid of Euler's formula, stated in the suggestion with Problem 4, write n=1 (-1)" a²+ n² eiax +e 2 Then use the series already obtained in that earlier problem. 2a sin an (-1)"+1 n² - a² (a cos nx n sin nx). - Cos nx -iax (n = 1, 2, ...). Cos nx

Linear Algebra: A Modern Introduction
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ISBN:9781285463247
Author:David Poole
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Chapter6: Vector Spaces
Section6.6: The Matrix Of A Linear Transformation
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Question
Can you do no 6
4. f(x) = eªx (−ï < x < ï), where a ‡ 0.
Suggestion: Use Euler's formula eie
=
Answer:
After evaluating this single integral, equate real parts and then imaginary parts.
sinh an 2 sinh an
+
Σ
ап
T
Answer:
an + ibn
5. f(x) = cosh ax (-л < x < л), where a
sinhan
ап
Answer:
0.
Suggestion: Use the series found in Problem 4.
T
π
=
- 1/2 [ + f(x) e¹/x dx
S
J
一元
∞
n=1
1
2a²
1+2a3 Σ
Σ -
n=1
+
8
cos+ i sin 0, where i = √-1, to write
(-1)"
a²+ n²
6. f(x) = cos ax (-л < x <л), where a 0, ±1, ±2, ... .
Suggestion: With the aid of Euler's formula, stated in the suggestion with
Problem 4, write
cos ax =
(-1)"
a²+ n²
eiax +e
2
Then use the series already obtained in that earlier problem.
2a sin an
(-1)"+1
n² - a²
n=1
(a cos nx n sin nx).
-
Cos nx
-iax
(n = 1, 2, ...).
Cos nx
Transcribed Image Text:4. f(x) = eªx (−ï < x < ï), where a ‡ 0. Suggestion: Use Euler's formula eie = Answer: After evaluating this single integral, equate real parts and then imaginary parts. sinh an 2 sinh an + Σ ап T Answer: an + ibn 5. f(x) = cosh ax (-л < x < л), where a sinhan ап Answer: 0. Suggestion: Use the series found in Problem 4. T π = - 1/2 [ + f(x) e¹/x dx S J 一元 ∞ n=1 1 2a² 1+2a3 Σ Σ - n=1 + 8 cos+ i sin 0, where i = √-1, to write (-1)" a²+ n² 6. f(x) = cos ax (-л < x <л), where a 0, ±1, ±2, ... . Suggestion: With the aid of Euler's formula, stated in the suggestion with Problem 4, write cos ax = (-1)" a²+ n² eiax +e 2 Then use the series already obtained in that earlier problem. 2a sin an (-1)"+1 n² - a² n=1 (a cos nx n sin nx). - Cos nx -iax (n = 1, 2, ...). Cos nx
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