4. Given the following set of stadia level notes: BACKSIGHT FORESIGHT STA STADIA VERTICAL ROD STADIA VERTICAL ROD ELEV INTERVAL INTERVAL READING INTERVAL INTERVAL READING A 1.75 -15°45' 2.10 425.15 ТР-1 2.15 -18°10' 1.92 1.55 +12°48' 1.58 3.20 -09°18' 1.65 The instrument used was a transit with an internal focusing telescope and a stadia interval factor of 98, and all linear measurements are in meters. FIND: A. The difference in elevation between station A and the turning point B. The elevation of TP-1 C. The elevation f B D. The difference in elevation between A and B.

4. Given the following set of stadia level notes: BACKSIGHT FORESIGHT STA STADIA VERTICAL ROD STADIA VERTICAL ROD ELEV INTERVAL INTERVAL READING INTERVAL INTERVAL READING A 1.75 -15°45' 2.10 425.15 ТР-1 2.15 -18°10' 1.92 1.55 +12°48' 1.58 3.20 -09°18' 1.65 The instrument used was a transit with an internal focusing telescope and a stadia interval factor of 98, and all linear measurements are in meters. FIND: A. The difference in elevation between station A and the turning point B. The elevation of TP-1 C. The elevation f B D. The difference in elevation between A and B.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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ANSWER KEY: D= 51.8319m∆h= 13.5430mElev Sta. A= 70.8530m
The following data were obtained by stadia observation: vertical angle, +12deg 30 min; upper stadia hair reading and lower stadia hair readings, 4.500 and 3.250m, respectively. The rod reading was taken at 3.875m above the stadia point at A and the height of instrument above the instrument station, B, is 1.620m. If the stadia interval factor is 99.5 and the instrument constant is 0.381m, compute the horizontal distance between theinstrument stationand the stadia point. Compute also the difference in elevation between the two ground points.
vertical angle is 30°23’, and observed stadia intercept is 2.20m. The stadia interval factor at the measurement used 95.50m and C is 0.30m, if the height of the instrument is 1.62m, and the rod reading is taken 1.95m. Determine the HD, VD, ID, and DE. Given:K= 95.5mS= 2.2mC = 0.3mVertical Angle = 30°23’
The following data were obtained by stadia observation: vertical angle, + 12deg 51 min; upper and lower stadia hair reading, 4.311 and 3.730 m, respectively. the rod reading was taken at 3.785m above the stadia point A and the height of instrument set up at point B is 1.620m. If the stadia interval factor is 99.5 and the stadia constant is 0.381m, what is the vertical distance? a.54.098 b.94.780 c.12.620 d.26.364
Transit is set up at A observed a stadia intercept of 2.2 m at a vertical angle of +18°23’. The stadia interval factor of the instrument used is 95.5 and stadia constant of 0.3 m. If the height of instrument is 1.62 m, and the rod reading is 1.95 m. Determine the vertical distance from the center of the instrument to the point on rod bisected by the horizontal cross hair.
The top of the mast signal 1750m away was sighted through a transit with recorded verticalangle of 4 0 55’. The height of the mast is 5.5m and the height of the instrument above the pointwhere it was set up is 1.15m. the elevation of the base of the signal ‘B’ is 167.23m, compute theelevation of the point under the transit ‘A’ with allowance due for curvature and refraction usingh= 0.067k^ 2
An engineer proceeded to do the stadia survey work to determine thetopography of a certain area. The transit was set up at a point A, with the line ofsight horizontal, took rod readings from the rods placed at B and C which is 200m. and 60 m. from A respectively. Rod at B has stadia intercept of 2.001 m. and0.600 m for Rod at C.a. Compute the stadia interval factor. b. Using the same instrument this was used for determining the elevation of PointD with a stadia intercept of 2.12 m. and a vertical angle of +4°22’. If theelevation of the point where the instrument was set up is 100 m., compute theelevation of Point D. Stadia constant is 0.30 m.c. Compute the horizontal distance from the point where the instrument was setup to Point D.
UPVOTE WILL BE GIVEN! Write the solutions legibly. Answer in 2 decimal places. FUNDAMENTALS OF SURVEYING When an alidade and a plane table were set up over a point the elevation of the line of sight of the alidade was 406.29m. In order to determine the elevation of point M. the stepping method was used. The interval intercepted between the stadio hairs on a rod held on M was 1.95m. After the line of sight was depressed for five steps from the horizontal line of sight, the rod reading at the horizontal cross hair was 2.62m. Determine the elevation of point M.
Compute for the coordinates of station O. Note that: A has a northing of 1620925.334 and easting of 507672.847. B has a northing of 1620923.996 and easting of 507617.614. C has a northing of 1620694.527 and easting of 507681.770. STATION OCCUPIED STATION OBSERVED HORIZONTAL ANGLE (m) O B 0˚00’00” A 0˚29’49” O A 0˚00’00” C 64˚08’18”
The upper and lower stadia hair readings on a stadia rod held at station B were observedas 3.50 and 1.00m respectively, with the use of a transit with an interval focusingtelescope and having a stadia interval factor of 99.5. The height of the instrument abovestation A is 1.45m and the rod reading is taken at 2.25m. If the vertical angle observed is-23034’, determine the following:a. Inclined stadia distanceb. Difference in elevation between the two stationsc. The elevation of station B, if the elevation of station A is 155.54m above mean sealevel.
The following data were obtained by stadia observation: vertical angle, + 12deg 51 min; upper and lower stadia hair reading, 4.311 and 3.730 m, respectively. the rod reading was taken at 3.785m above the stadia point A and the height of instrument set up at point B is 1.620m. If the stadia interval factor is 99.5 and the stadia constant is 0.381m, what is the difference in elevation? a.10.455 b.24.109 c.20.852 d.34.321
Given:Upper reading = 1.64 mMiddle reading = 1.57 mLower reading = 1.51 mVertical Middle Angle = 10°32’00”Elev of point A = 333 mH of instrument = 1.2 mK = 100Stadia Constant = 0 Solve the ff.: A. Inclined, horizontal, and vertical distance B. Elevation of point B.