4. In hogs a gene that produces a white belt (B) around the animal's body is dominant over the allele for a uniformly colored body (b). An allele on a different gene produces fusion of the two hooves on each foot and this allele (F) is dominant over the allele for normal/non-fused hooves (f). Assume that a uniformly colored, normal footed hog is mated to a hog that is homozygous for the belted character and fused hooves. a. What is the phenotypic ratio for the F1 generation? Assume the F1 individuals were allowed to breed freely among themselves. Show the Punnett square for the cross between F1 individuals. b. C. Write the phenotypic ratio for the F2 generation.

4. In hogs a gene that produces a white belt (B) around the animal's body is dominant over the allele for a uniformly colored body (b). An allele on a different gene produces fusion of the two hooves on each foot and this allele (F) is dominant over the allele for normal/non-fused hooves (f). Assume that a uniformly colored, normal footed hog is mated to a hog that is homozygous for the belted character and fused hooves. a. What is the phenotypic ratio for the F1 generation? Assume the F1 individuals were allowed to breed freely among themselves. Show the Punnett square for the cross between F1 individuals. b. C. Write the phenotypic ratio for the F2 generation.

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Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

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1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
4) In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown in the image attached. a) Assign the letter “s” to the wing pattern gene and letter “w” to the background color gene. Write in the capital letter for the dominant phenotype and the lower case letter for the recessive phenotype. Also, write whether each allele is dominant (D) or recessive (R). Wing pattern gene: Spotted - letter assignment:____ - dominant or recessive:____ Striped - letter assignment:____ - dominant or recessive:____ Background color gene: orange: - letter assignment:____ - dominant or recessive:____ white: - letter assignment:____ - dominant or recessive:_____ b) Based on the four matings in Question 4: What are the genotypes of each parent in each cross? If more…
4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)
4. Huntington diseases is a rare fatal, degenerative neurological disease in which individuals start to show symptoms in their 40s. It is caused by a dominant allele. Joe, a man in his 20s, just learned that his father has Huntington disease. a. What is the probability that Joe will also develop the disease?b. Joe and his new wife have been eager to start a family. What is the probability that their first child will eventually develop the disease?
2. In four-o’clocks, the allele for red flowers is incompletely dominant to the allele for white flowers, soheterozygotes have pink flowers. What ratios offlower colors would you expect among the offspringof the following crosses: (a) pink × pink, (b) white ×pink, (c) red × red, (d) red × pink, (e) white × white,and (f) red × white? If you specifically wanted to produce pink flowers, which of these crosses would bemost efficient?
2.In dogs, there is a hereditary deafness caused by a recessive allele, d. A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, but the owner is unsure of the genotype. She does a testcross (crosses it to a homozygous recessive dog), and two of the five offspring are deaf. This means that the male dog A.has the genotype DD B.has the genotype Dd C.is still of unknown genotype since there were offspring of both deaf and hearing phenotypes. D.has the genotype dd
4.Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene—an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). The allele for long eyelashes is dominant (L) and the allele for short eyelashes is recessive (l). An individual who is heterozygous for eyelash length would have which of the following genotypes? A.Short eyelashes B.Ll C.LL D.Long eyelashes
3. Codominance is when two dominant alleles of contrasting pair fully expressed at the same time in heterozygous individual. Which of the following situation is an example ofcodominance?A. Jo mated the red bull with the white cow to produce a roan cow.B. Melissa traces her blood type by crossing the blood type of herparents.C. James passed a genetic disorder hypertrichosis pinnae aurisor hairy ear to his son.D. Tess crosses the red carnation flower plant with white flowercarnation plant to produce a pink flower plant.
5. In the fruit fly Drosophila melanogaster, very dark(ebony) body color is determined by the e allele. Thee+ allele produces the normal wild-type, honeycolored body. In heterozygotes for the two alleles (butnot in e+e+ homozygotes), a dark marking called thetrident can be seen on the thorax, but otherwise thebody is honey-colored. The e+ snd e alleles are thusconsidered to be incompletely dominant.a. When female e+e+ flies are crossed to male e+eflies, what is the probability that progeny will havethe dark trident marking?b. Animals with the trident marking mate amongthemselves. Of 300 progeny, how many would beexpected to have a trident, how many ebony bodies, and how many honey-colored bodies?
4. The inheritance of coat colour in cattle controlled by multiple alleles with a dominance hierarchy as follows: S > sh > sc > s. The S allele produces a white band all over the cattle’s body known as ‘Dutch band’, the sh allele produces spots on the skin known as ‘Hereford’, the sc allele produces solid colour, and the s allele produces ‘Holstein’ spots. Homozygous ‘Dutch band’ males are cross to ‘Holstein’ females. The F1 females are crossed to ‘Hereford’ males of the shsc genotype. With the aid of genetic diagram, determine the expected genotypic and phenotypic frequencies in the F2 progeny.
4. Marfan syndrome is a genetic trait caused by in a dominant allele. The trait causes a weakening of the aorta that can be fatal. A teenager whose mother has the syndrome (but whose maternal grandfather was not affected), and whose father was unaffected, is concerend that she may have the trait. a. What is the phenotype of each of her parents? Genotype? b. What is the chance that the teenager has Marfan syndrome?
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?