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- 4. If the secant method is used on f(x) = x^5 +x^3 +3 and if x_(n-2) = 0 and x_(n-1) = 1, what is x_n?lim y approaches 0 ................... [5y3 + 8y2]/[3y4 - 16y2]Evaluate the following: 1. lim √(6-y) - 2 y-> 2- y2 - 4 y + 4 2. lim |2t-1| - |2t+1| t-> 0- |t|3. lim ( v2 [[v]] - |v-4| ) v-> 2-4. lim [[x]] - |x| x-> 0+ [[x]] + 1