4. Solve the differential equation: x(y - 1) dx + (x + 1) dy = 0. If y = 2 when x = 1. A. 1.80 B. 1.48 C. 1.55 D. 1.63

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3. The equation y² = cx is general solution of:
A. y' = 2y / x
B. y' = 2x / y
C. y'=y/2x
D. y' = x/2y
4. Solve the differential equation: x(y − 1) dx + (x + 1) dy = 0.
If y = 2 when x = 1.
A. 1.80
B. 1.48
C. 1.55
D. 1.63
5. Solve (cox x cos y − cotx) dx - sin x sin y dy = 0
A. sin x cos y = ln (c cos x)
B. sin x cos y = ln (c sin x)
C. sin x cos y = -ln (c sin x)
D. sin x cos y = -ln (c cos x)
6. Find the differential equation whose general solution is y =
C,x + C,e¹.
A. (x - 1) y" - xy' + y = 0
B. (x + 1) y" − xy + y = 0
C. (x − 1) y” + xy' + y = 0
D. (x + 1) y" + xy' + y = 0
7. Find the general solution of y' = y sec x
A. y = C (sec x + tan x)
B. y = C (sec x - tan x)
C. y = C (sec x tan x)
D. y = C (sec2 x + tan x)
8. Solve xy' (2y - 1) = y(1-x)
A. ln (xy) = 2 (x−y) + C
B. ln (xy) = x - 2y + C
C. ln (xy) = 2y - x + C
D. In (xy) = x + 2y + C
Transcribed Image Text:3. The equation y² = cx is general solution of: A. y' = 2y / x B. y' = 2x / y C. y'=y/2x D. y' = x/2y 4. Solve the differential equation: x(y − 1) dx + (x + 1) dy = 0. If y = 2 when x = 1. A. 1.80 B. 1.48 C. 1.55 D. 1.63 5. Solve (cox x cos y − cotx) dx - sin x sin y dy = 0 A. sin x cos y = ln (c cos x) B. sin x cos y = ln (c sin x) C. sin x cos y = -ln (c sin x) D. sin x cos y = -ln (c cos x) 6. Find the differential equation whose general solution is y = C,x + C,e¹. A. (x - 1) y" - xy' + y = 0 B. (x + 1) y" − xy + y = 0 C. (x − 1) y” + xy' + y = 0 D. (x + 1) y" + xy' + y = 0 7. Find the general solution of y' = y sec x A. y = C (sec x + tan x) B. y = C (sec x - tan x) C. y = C (sec x tan x) D. y = C (sec2 x + tan x) 8. Solve xy' (2y - 1) = y(1-x) A. ln (xy) = 2 (x−y) + C B. ln (xy) = x - 2y + C C. ln (xy) = 2y - x + C D. In (xy) = x + 2y + C
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