4. Suppose the Supply function for a product is given as p = 30 + 0.001x² and the Demand function is given as p = 90 - 0.3x %3D a. Sketch the graph of the two functions, for 0
4. Suppose the Supply function for a product is given as p = 30 + 0.001x² and the Demand function is given as p = 90 - 0.3x %3D a. Sketch the graph of the two functions, for 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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Need help and want to know steps, plus which of the tattoo formulas i have to use if needed
Transcribed Image Text:4. Suppose the Supply function for a product is given as p = 30 + 0.001x² and the Demand function is
given as p = 90 – 0.3x
a. Sketch the graph of the two functions, for 0<x<300. Make sure to LABEL your x and y axes with
their scales.
b. Find the point of intersection between the two functions. You do not need to do this algebraically.
c. Find the Consumer's Surplus using calculus.
Transcribed Image Text:*TATTOO"CHEAT SHEET - USE OFTEN!
youR
THE BASICS
derv.
PX) MP
CO) MC
RX) MR
X→ fcx)+y (ly CAN BE +,Ø,-)
X f'x) SLOPE(SLOPE CAN BE +,Ø,
integ.
- {0 = MAx OR MIN OR H.P.I.3)
X *f"(x) + CONCAVITY (CONCAVITY IS ,A,Ø { Bis POINT OF INFLECTION})
DERIVATIVES
PRODUCTS AND QUOTIENTS
u isA
FUNCTION,
X IS VAR.,
e AND n y= u y'= u'v -uv'
y=x^
y'= nxn-i
U AND V
youv y'- u'v+uv'
%3D
n-I
y'= nu" (u')
y=e" y'- u'e"
y=Lnu y'= 4 doutdin
y=u^
ARE
FUNCTIONS
CONSTANTS
LOGS AND EXPONENTS
y=a" y'=a"u'ına ) WHERE U
y-a* y = a*x' In a fa is const,
Fa*(1) ina
INTEGRALS
IS A FUNC,
x^dx
+K, n+-I
X IS VARVABLE
ntl
dx → U'
+k, n+-1
Un(e*) =x (SIMPLIFIED, NOT DERIVATI VE )
=X (SIMPUFIED, NOT DERIVATIVE)
y= Ju'e"dr → e" + k
in(MN) = Ln M+ inN
in (A) - LnM -UnN
in (M) = PlnM
y= logax ay =x
WHERE M
» In u +K n=-l
EN ARE
STEPS
FUNCTIONS.
(CONVERSIONS
NOT DERIVATIVĖS
1) MAKE IT PRETTY. WHICH INTEGRAL?
2) FIND U; CREATE U'
3) WE HAVE
4) MAKE IT LOOK LIKE TEMPLATE
5) PERFORM INTEGRAL
WE WANT.
CHANGE OF BASE:
y=loga x
loga
DEFINITE INTEGRALS
log X
In X
%3D
ALSO
Una
y=Jax^dx = afx°dx
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