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Electrical EngineeringQ&A Library4. The amplifier shown below has voltage gain v v, equal to 150. Calculatea) The lower cutoff frequency.b) The frequency at which vi leads Vs by 50° Ans. 28.875 Hz(c) The voltage gain |v |/v, two octaves above cutoff. (HintYLLELİİVLİ as in Example 9-5.) Ans. 72.761Ans. 34.412 Hz3.7 μF_가625 2625 ΩQuestion

Asked May 5, 2019

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I got parts a & b right. I just need a clarification how the author got the answer to part c 72.761

Step 1

From Part (a), the lower cutoff frequency (*f _{L}*) is 34.412 Hz.

Step 2

Write the expression for required voltage gain as follows:

Step 3

From the amplifie...

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