4. The population of a trading area is currently 100 thousand. At time t years from now population will be growing at the rate of 20 (0.5t + 9)Z thousand per year. a) What will total population be 11 years from now? b) How long will it take the population to reach 260 thousand?

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A: Let's find.

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A: The solution is given below in the next step:

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A:

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A: Given. P1'(t) = 90e0.1t (1000$) P2'(t) = 140e0.07t (1000$)

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A: Solution : Given that element X is a radioactive isotope such that every 70 years, its mass…

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A: Here we have consider 3 lakes. i.e A,B and C.                               Volume of lake B=2650…

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A:

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A:

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A:

Q: 3. If a radioactive substance is quickly decaying at a rate of 13% per hour approximately how much…

A:

Q: As an active environmentalist who is interested in the impact of climate change on sea level, you…

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A:

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A: Given that,initial principal amount,P=4200 Rate of interest,i=0.038 Number of years of deposit,N=4

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A: The given question can be solved as shown in step2.

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A: This question is related to population growth, We will solve it using integration.

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A:

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