number 4 only. ashdbaefbaj 1. y = 10x – x², the x-axis and the lines x = 2 and x = 52. 2x + y = 6, the coordinate axes3. у %3D2х + 1, х +у%3D7, х %3D84. у2 %3D2х, у %3Dх— 45. y = x³, y = 4x [first quadrant]6. у2 %3D х3, у %3 2х7. у %3Dх2 — 4, у %3D 2х- х28. the first quadrant area of the circle x2 +y2 = a?9. the region enclosed by b?x? + azy2 = a²b² in the firstquadrant%3D

(4). Given: y2=2x & y=x-4 Now find the point of intersection between the curve and line; y2=2x…

Answered: 4. у2 %3D 2х, у %3 х— 4

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter8: Introduction To Functions

Section8.10: Inverse Variation

Problem 1MRE

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