4. Write a SQL query to find the name of oldest sailors for each rating level. 5. Find the average age of sailors for each rating level that has at least two sailors. 6. Write a SQL query to find the average number boats reserved by different sailors.

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question 3: SQL Queries
Sailors(sid: integer, sname: string, rating: integer, age: real);
Boats(bid: integer, bname: string, color: string);
Reserves(sid: integer, bid: integer, day: date).
4. Write a SQL query to find the name of oldest sailors for each rating level.
5. Find the average age of sailors for each rating level that has at least two sailors.
6. Write a SQL query to find the average number boats reserved by different sailors.
7. Write a SQL query to find the names of sailors who reserved all non-blue boats.
8. Write a SQL query to find the name of the boat that is most popular one.
9. What does the following two queries do?
SELECT sid
FROM s
SELECT sid
FROM s
WHERE rating > all (
SELECT rating
s s2
WHERE s2.sname='Bob’)
WHERE rating > any (
SELECT rating
s s2
WHERE s2.sname='Bob'))
FROM
FROM
Transcribed Image Text:Question 3: SQL Queries Sailors(sid: integer, sname: string, rating: integer, age: real); Boats(bid: integer, bname: string, color: string); Reserves(sid: integer, bid: integer, day: date). 4. Write a SQL query to find the name of oldest sailors for each rating level. 5. Find the average age of sailors for each rating level that has at least two sailors. 6. Write a SQL query to find the average number boats reserved by different sailors. 7. Write a SQL query to find the names of sailors who reserved all non-blue boats. 8. Write a SQL query to find the name of the boat that is most popular one. 9. What does the following two queries do? SELECT sid FROM s SELECT sid FROM s WHERE rating > all ( SELECT rating s s2 WHERE s2.sname='Bob’) WHERE rating > any ( SELECT rating s s2 WHERE s2.sname='Bob')) FROM FROM
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