SOLVE THE PROBLEMS WITH METHOD OF JOINTS AND METHOD OF SECTIONS4.152 Compute the forces in members EF, NF, and NO.Please answerNumber questionnumber 2GLMNP300 kN-8 panels e 5m- 40 m-Dimensions in metersFig. P4.152, P4.1534.153 Repcat Prob. 4.152 assuming that the 300-kN force is applied at 0'insteadof L.

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4.152 Compute the forces in members EF, NF, and NO. Please answer Number question number 2 G H 4. LMNO 300 KN -8 panels e 5 m= 40 m- Dimensions in meters Fig. P4.152, P4.153 4.153 Repcat Prob. 4.152 assuming that the 300-kN force is applied at O instead 625 09

4.152 Compute the forces in members EF, NF, and NO. Please answer Number question number 2 G H 4. LMNO 300 KN -8 panels e 5 m= 40 m- Dimensions in meters Fig. P4.152, P4.153 4.153 Repcat Prob. 4.152 assuming that the 300-kN force is applied at O instead 625 09

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

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