4.35 When we decompose a vector space as a direct sum, the dimensions of the subspaces add to the dimension of the space. The situation with a space that is given as the sum of its subspaces is not as simple. This exercise considers the two-subspace special case. (a) For these subspaces of M2x2 find W₁ W₂, dim(W₁ W₂), W₁ + W₂, and dim(W₁ + W₂). W₁ = {(d) | c, d = R} W₂ = {(b) | b, c € R} (b) Suppose that U and W are subspaces of a vector space. Suppose that the sequence (B1,..., Bk) is a basis for Un W. Finally, suppose that the prior sequence has been expanded to give a sequence (μ₁,..., ₁, B₁,..., ßk) that is a basis for U, and a sequence (B₁,..., Bk, w₁,..., wp) that is a basis for W. Prove that this sequence (μ₁, ..., µj, B1, ..., Bk, w1,..., p) is a basis for the sum U + W. (c) Conclude that dim(U+W) = dim(U) + dim(W) - dim(Unw). (d) Let W₁ and W₂ be eight-dimensional subspaces of a ten-dimensional space. List all values possible for dim(W₁ W₂).

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Chapter5: Inner Product Spaces
Section5.CR: Review Exercises
Problem 41CR: Let B={(0,2,2),(1,0,2)} be a basis for a subspace of R3, and consider x=(1,4,2), a vector in the...
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Please do Exercise 4.35 part ABCD and please show step by step and explain

4.35 When we decompose a vector space as a direct sum, the dimensions of the
subspaces add to the dimension of the space. The situation with a space that is
given as the sum of its subspaces is not as simple. This exercise considers the
two-subspace special case.
(a) For these subspaces of M2x2 find W₁
W₂, dim(W₁ W₂), W₁ + W₂, and
dim(W₁ + W₂).
W₁ = {(d) | c, d = R}
W₂ = {(b) | b, c € R}
(b) Suppose that U and W are subspaces of a vector space. Suppose that the
sequence (B1,..., Bk) is a basis for Un W. Finally, suppose that the prior
sequence has been expanded to give a sequence (μ₁,..., ₁, B₁,..., ßk) that is a
basis for U, and a sequence (B₁,..., Bk, w₁,..., wp) that is a basis for W. Prove
that this sequence
(μ₁, ..., µj, B1, ..., Bk, w1,..., p)
is a basis for the sum U + W.
(c) Conclude that dim(U+W) = dim(U) + dim(W) - dim(Unw).
(d) Let W₁ and W₂ be eight-dimensional subspaces of a ten-dimensional space.
List all values possible for dim(W₁ W₂).
Transcribed Image Text:4.35 When we decompose a vector space as a direct sum, the dimensions of the subspaces add to the dimension of the space. The situation with a space that is given as the sum of its subspaces is not as simple. This exercise considers the two-subspace special case. (a) For these subspaces of M2x2 find W₁ W₂, dim(W₁ W₂), W₁ + W₂, and dim(W₁ + W₂). W₁ = {(d) | c, d = R} W₂ = {(b) | b, c € R} (b) Suppose that U and W are subspaces of a vector space. Suppose that the sequence (B1,..., Bk) is a basis for Un W. Finally, suppose that the prior sequence has been expanded to give a sequence (μ₁,..., ₁, B₁,..., ßk) that is a basis for U, and a sequence (B₁,..., Bk, w₁,..., wp) that is a basis for W. Prove that this sequence (μ₁, ..., µj, B1, ..., Bk, w1,..., p) is a basis for the sum U + W. (c) Conclude that dim(U+W) = dim(U) + dim(W) - dim(Unw). (d) Let W₁ and W₂ be eight-dimensional subspaces of a ten-dimensional space. List all values possible for dim(W₁ W₂).
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