4.4-1 AHSS10 × 8 × 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for A500 Grade B steel (Fy = 46 ksi). Note that thisis a slender-element compression member, and the equations of AISC Section E7 mustbe used.

4.4-1 AHSS10 × 8 × 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute the nominal compressive strength for A500 Grade B steel (Fy = 46 ksi). Note that thisis a slender-element compression member, and the equations of AISC Section E7 mustbe used.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter4: Compression Members

Section: Chapter Questions

Problem 4.8.1P

See similar textbooks

Related questions

Q: Aconcrete sectionwith b = 16 in. and d = 19.5 in. is required to develop a bending moment strength…

A: Given Concrete b=16in. d=19.5 in. Mr=400 kip-ft Mr=4800 kip-inch f'c=4ksify=60ksi

Q: Compute the nominal compressive strength for a WT10.5 x 91 with an effective length of 18 feet with…

A: For the section 10.5*91 the section properties: Ag=26.8 in2 ry=3 in rx=3.07 in

Q: A simply supported rectangular beam of length L=5.4m has a width of b=395mm and an effective depth…

A: The values given in the question are as follows Length(L)=5.4 m Width(b)=395 mm Effective…

Q: Question 5 of 20 A structural member is fabricated with the cross section show below and is…

Q: A Doubly Reinforced concrete beam has an effective depth of 600mm and a width of 325mm. It is…

A: Note- Ultimate moment capacity value written is a wrong value. After calculation its exact value is…

Q: 8. HSS 10 x 8 x1/4 with Fy-50 ksi is selected to be used as a compression member with KL=10ft.…

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: For the beam shown below, determine the concrete and steel stresses at the locations of the maximum…

A: In solid mechanics, a bending moment can be defined as a response that occurs in a structural…

Q: A W10x112 column rest on a base plate and on a 400 mm x 400 mm concrete pedestal. The pedestal and…

Q: 3. Given the following information, determine the maximum permissible axial load in the square…

A: Given:- The longitudinal reinforcing bars = 4-#10 bars The yield strength of the steel = fy = 60 ksi…

Q: P Bearing plate Let the allowable stresses in the post be ost=120MPaand oco=6MPA. Compute the…

A: Solution-The given data ,σst=120MPaσco=6MpaModulus of elasticity=200GPa and For concrete 14GPaCross…

Q: snip

A: The factored axis load is Pu=1.6×28=44.8kipsthe factored transversed load and bending moment…

Q: Determine the maximum bending stress on the section.

Q: Use A992 steel and compute the nominal compressive strength of a WT12 x 51.5 with an effective…

Q: A W14 x 90 section is to be used as column with a length of 30 ft. The column supports an axial load…

A: Eccentric load: The external load whose line of action is parallel but does not coincide with the…

Q: A compression member with an effective length of KL = 12 ft is built up from a W shape and a…

Q: 1.) The beam has a width of 300 mm, an overall depth of 600 mm, and an effective depth of 520 mm.…

Q: A secondary compression member has an effective length of 7.2 m with a cross section area of 0.0084…

A: Given: The effective length is 7.2 m. The cross-section area is 0.0084 m2. The moment of inertia is…

Q: A W10 x 22 of A36 steel is used as a 15-ft long pinned ends column. Compute the column's buckling…

A: For section W10×22area Ag=6.49 in2length L=15 mboth end are pinned then KL=0.5×15=7.5…

Q: Rigid beam AB is supported by three bolts at A and a pin at B. The bolts at A are in double shear…

Q: 1. A W12 x 65 of A572 Grade 60 (Fy = 60 ksi) steel is used as a compression member. It is 26 feet…

A: LFRD LFRD means Load and Resistance Factor for Design. LFRD method is used to design structures and…

Q: A column is to support an axial dead load of 900 kN and an axial live load of 1240 kN. Use fy = 414…

A: Given data: DL=900 KNLL=1240 KNfy=414 MPafc'=27.6 MPaAst=2%Agϕmain=28 mm We need to design the…

Q: A simply supported beam 4 m long is carrying a variable load of w = 0 KN/m at the left support and w…

Q: If the F = { - 200i + 400j } N , determine the force in each member and state if its in compressions…

Q: A W310 X 117 of Grade 60 steel is used as a compression member. It is 8.5m long, pinned at each end,…

A: Given, DL = 800 kN LL = 1420 kN

Q: Determine the flexural capacity of the given section of beam below. b=340 d=470 d'=75 fc'=28 fy=300…

A: Answer We can determine the flexural capacity of the given section and NSCP 2015 for doubly…

Q: A compression member is built up from a W14 X 90 and a W10 x 49, both A992 steel. W14 x 90 7" W10x…

Q: 8. HSS 10 x 8 x1/4 with Fy=50 ksi is selected to be used as a compression member with KL=10ft.…

A: 8) E = 29,000 ksi For, HSS 10 X 8 X 1/4 ; Iy = 84.7 in4 , A = 8.03in2 So, rmin = (Iy/A )0.5 = 3.248…

Q: A W12 x 65 of A572 Grade 60 steel (Fy = 414 MPa, Fu = 520 MPa)l is used as a compression member. It…

Q: Q-2: A rectangular concrete beam of width, b= 32-inch is limited by architectural consideration to…

Q: A W21 x 101 is used as compression member with one end fixed and the other end free. The length is…

A: Question is based on the compression member with one end fixed and the other end free . Length of…

Q: Determine the amplification factor for the following braced column (W21x44) (A992 steel). The…

A: Section=W21x44, Loads on the column: PL=100 k, PD=220 k.

Q: Rigid beam AB is supported by three bolts at A and a pin at B. The bolts at A are in double shear…

Q: Q: For the built-up shape shown in Figure, assume that the components of the cross section are…

A: Yield strength of steel (Fy) = 50 ksi Cross-section details: Longitudinal profiles:

Q: plates. Additional connection requirements are given for other built-up compression members compesed…

A: The given figure is shown below:

Q: A W310 X 117 of Grade 60 steel is used as a compression member. It is 8.5m long, pinned at each end,…

A: Given data:- Steel grade is 60 W section is W310×117 Service deal load, DL = 800 kN Service Live…

Q: Design for the circular section the maximum uniformly distributed load that can be loaded for the…

A: While twisting disappointment is generally found with long bar ranges conveying uniform burdens,…

Q: A rectangular beam has a width of 300mm and an effective depth of 537.50 mm to the centroid of…

Q: 4.4-2 A W21 × 101 is used as a compression member with one end fixed and the other end free. The…

Q: Aconcrete sectionwith b = 16 in. and d = 19.5 in. is required to develop a bending moment strength…

A: Given:- b = 16 in d = 19.5 in Mr=1400 kip-ft = 16800 kip inch f'c=4ksi fy = 60 ksi To find:--…

Q: steel, determine the safe load P based on the cap= strut with a cross section as shown. Use LRFD. y…

A: The properties for the section C9*20 are: depth, d=9 in bf=2.648 in Cxx=0.583 in Area=5.8 in2…

Q: Determine the theoretical steel areas required for compression (A's) of a rectangular…

Q: A column section I.S.H.B. 350 @ 661.2 N/m carries an axial load of 1100 kN. Design a suitable gusset…

Q: Determine the ASD design strength (kN) of th between the supports is 510 cm. Use the reco section…

Q: 3-3 A rectangular section with width b=200mm and depth h=450mm is reinforce with 4 16 of HRB400, The…

A: Width (b) = 200 mm Depth (h) = 450 mm Reinforcement of concrete = 4 -16 diameter HRB400 Design…

Q: A double-MC shape, 2MC18x42.7 with cover plate PL 0.41x13 of 50-ksi steel is used for a built-up…

A: Given data:-Double MC shape, 2MC18×42.7 Cover plate, PL 0.41×13 Thickness of plate, t=0.41 in Width…

Q: Determine the safe load P that the member below can carry. Use A-36 steel and NSCP 2001 L3X2.5X1/4…

A: Given steel angle leg section is L3×2.5×14 , where d=3in, bw=2.5in, t=14 for plate the dimensions…

Q: Determine the safe load P that the member below can carry. Use A-36 steel and NSCP 2001 L3X2.5X1/4…

A: Properties of L3x2.5x0.25,From AISC shape database,x1 = x-centroid = 0.90 iny1 = y-centroid =…

Q: Example : 5.2 A column section I.S.H.B. 350 @ 661.2 N/m carries an axial load of 1100 KN. Design a…

Q: A WT305 x 41 standard steel shape is used to support the loads shown on the beam. The dimensions…

A: Draw the free-body diagram of the beam. For section WT 305×41, Iz=48.7×106 mm4

Q: Question 6: .PL눌X 12 Determine the LRFD design compressive strength for the shown built-up…

Question

4.4-1

AHSS10 × 8 × 3⁄16 is used as a compression member with one end pinned and the other end fixed against rotation but free to translate. The length is 12 feet. Compute

the nominal compressive strength for A500 Grade B steel (Fy = 46 ksi). Note that this
is a slender-element compression member, and the equations of AISC Section E7 must
be used.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Trending now

This is a popular solution!

Step by step

Solved in 6 steps with 7 images

SEE SOLUTION Check out a sample Q&A here

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

the textbook solution at the back says the answer is 161 kips. But I'm not sure if the error is from the book for this solution.

Solution

by Bartleby Expert

SEE SOLUTION

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A W21 x 101 is used as compression member with one end fixed and the other end free. The length is 10 feet. What is the nominal compressive strength if Fy 5 50 ksi? Note that this is a slender-element compression member, and the equations of AISC Section E7 must be use
A W21 × 101 is used as a compression member with one end fixed and the other end free. The length is 9m. Fy = 345 MPa. 1. What are the slenderness limits for the W-section?2. What is the nominal compressive strength?
4.4-2 A W21 × 101 is used as a compression member with one end fixed and the other endfree. The length is 10 feet. What is the nominal compressive strength if Fy = 50 ksi?Note that this is a slender-element compression member, and the equations of AISCSection E7 must be used. 4.6-2 A 15-foot long column is pinned at the bottom and fixed against rotation but free totranslate at the top. It must support a service dead load of 100 kips and a service liveload of 100 kips.a. Select a W12 of A992 steel. Use the column load tables.1. Use LRFD.2. Use ASD.b. Select a W16 of A992 steel. Use the trial-and-error approach covered in Section 4.6.1. Use LRFD.2. Use ASD.
A simply supported rectangular beam of length L=5.4m has a width of b=395mm and an effective depth ofd=311m. Compression steel bars are placed at a distance d′=155mm from the extreme concrete compressivefiber. The beam supports service dead loads of Wd=27.5KN/m and Wl=35.5KN/m, respectively. Use fc′ = 28MPaand fy= 420 MPa. For the reinforcements, use 4 25 mm tension steel bars and 4 12 mmcompression steel bars.
Aconcrete sectionwith b = 16 in. and d = 19.5 in. is required to develop a bending moment strength ofMr = 400 kip-ft. Use of compressivereinforcement is desired. Find the required reinforcement. Use f ′ c = 4 ksi and fy = 60 ksi.
Compute the nominal compressive strength for a WT10.5 x 91 with an effective length of 18 feet with respect to each axis. Use A992 steel and the procedure of AISC Section E4 (not the column load tables).
A W 360 x 44 of A992 steel column (Fy =345 MPa) having a length of 4m is fixed at both ends. Compute the effective width, be, of the slender web.Compute the value of reduction factor, Q, due to slender elementsin compression members.Compute the nominal compressive strength of the W-section.Properties of W 360 x 44Ag = 5710 mm2d = 351 mmbf = 171 mmtf = 9.78 mm tw = 6.86 mmkdes = 19.9 mmk1 = 19.1 mmrx = 146 mmry = 37.8 mm
OOO OOOO OOOO SITUATION 2: A W 16 x 58 beam is connected to W 18 x 31 column. A36 steel has an Fy = 248 MPa. Allowable bearing stress is 1.35Fy. Using a 502 grade hot driven rivets, with allowable shearing stress of 120 MPa. The support is to be designed using the full strength 2290x90x10 of W16 x 58 beam based on the gross section. Properties of section: W 16 x 58 W 18 x 31 fv = 0.40 Fy te = = 11 mm d = 403 mm tw = 10 mm W18x31 W16x58 4. Which of the following most nearly gives the minimum diameter of rivets so that allowable shear stress will not be exceeded? 23 mm o b. 25 mm 0 28 mm d. 30 mm 0 5. Which of the following most nearly gives the minimum diameter of rivets not to exceed allowable bearing stress? 23 mm 0 b. 25 mm o 28 mm • d. 30 mm 0 6. Which of the following most nearly gives the minimum diameter of rivets? 23 mm o b. 25 mm o 28 mm • d. 30 mm 0 a. C. a. C. a. C.
– A W460 × 177 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 3.70 meters. If A992 steel is used, what is the available compressive strength? Compute both the design strength for LRFD and the allowable strengthfor ASD.
A built-up beam made from fastening two channels to a wide flange section carriesloads` as shown. The fasteners are 12mm∅ bolts with allowable shear stress τ= 110 MPa. Forbearing, σb= 220MPa for single shear, and σb= 275 MPa for double shear. E=200 GPA. Fy=420MPa. Do not round off between solutions Determine the flexural stress at fiber 30 mm above Neutral Axis at distance 5 metersfrom the support at A.
A built-up beam made from fastening two channels to a wide flange section carriesloads as shown. The fasteners are 12mm∅ bolts with allowable shear stress τ= 110 MPa. Forbearing, σb= 220MPa for single shear, and σb= 275 MPa for double shear. E=200 GPA. Fy=420MPa. 1. Determine the Moment of Inertia of the Section2. Determine the Moment Capacity of the section if fb≤280MPa.3. Determine the flexural stress at fiber 30 mm above Neutral Axis at distance 5 metersfrom the support at A.
A built-up beam made from fastening two channels to a wide flange section carriesloads` as shown. The fasteners are 12mm∅ bolts with allowable shear stress τ= 110 MPa. Forbearing, σb= 220MPa for single shear, and σb= 275 MPa for double shear. E=200 GPA. Fy=420MPa. 1. Determine the Moment of Inertia of the Section2. Determine the Moment Capacity of the section if fb≤280MPa.3. Determine the flexural stress at fiber 30 mm above Neutral Axis at distance 5 metersfrom the support at A.4. Determine the maximum bending stress on the section.5. Determine the maximum shearing stress at Neutral Axis.6. Determine the horizontal shearing stress at 20 mm above the Neutral Axis.7. Determine the horizontal shearing stress at 95 mm above the Neutral Axis.8. Determine the spacing of the bolts. Answer only the number 4-6. Thank you!