Question
Asked Oct 15, 2019
4.8
Use the superposition principle to find voltages V
V and V, in the eircuit shown in Figure P48.
FIGURE P4.8
1
Wr
3 k
0 mA
2 mA
3 kn
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4.8 Use the superposition principle to find voltages V V and V, in the eircuit shown in Figure P48. FIGURE P4.8 1 Wr 3 k 0 mA 2 mA 3 kn

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check_circleExpert Solution
Step 1

Apply superposition principle to the given circuit.

Step 1: Open-circuit the current source 2 mA and find the node voltages.

The modified the given figure by open-circuiting the 2 mA current source as shown in Figure 1.

W
1 kΩ
R2
V2
V3
W
VI
1 ΚΩ
3k2
R4
3 ΚΩ
10 mA
Is
0
Figure 1
W
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W 1 kΩ R2 V2 V3 W VI 1 ΚΩ 3k2 R4 3 ΚΩ 10 mA Is 0 Figure 1 W

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Step 2

Apply KCL to Figure 1 and write the following equations.

И-и И-,
10mA
1
(1)
+
3kQ
1kQ
V
V-V
V-V
2
2
1
2
(2)
lk2
3k2
3 kQ
V, -V
V-V
0
1k2
1
2
(3)
1kΩ
By solving Equations (1), (2), and (3), the node voltage values are,
V 42V
V = 30V
V 36V
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И-и И-, 10mA 1 (1) + 3kQ 1kQ V V-V V-V 2 2 1 2 (2) lk2 3k2 3 kQ V, -V V-V 0 1k2 1 2 (3) 1kΩ By solving Equations (1), (2), and (3), the node voltage values are, V 42V V = 30V V 36V

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Step 3

Step 2:

Open-circuit the current source 10 mA and find the node voltages.

The modified figure ...

1 kΩ
R3
R2
V2
V3
Vi
1k2
3 kΩ
R4
2 mA
3 ΚΩ
Is
Figure 2
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1 kΩ R3 R2 V2 V3 Vi 1k2 3 kΩ R4 2 mA 3 ΚΩ Is Figure 2

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