42. What is the polynomial equation whose roots are {-2, 2, and 4 of multiplicity 2} A. 2x* - 2x + 4x? - 4x = 0 B. x*- 8x + 12x? + 32x - 64 = 0 C. 2x* - 8x + 2x? - 8x - 8 = 0 D. x* + 12x? + 32x - 64 0 43. When x + 3x2 + mx + n is divided by (x + 2), the remainder is 9. When it is divided by (x - 3), the remainder is 49. What is the value of m? A. 1 В. 2 С. -2 D. -1 44. What are the possible rational roots of the equation 2x* - 8x³ + 2x² - 8x - 6 = 0? A. 土1,土2,土3,土6,土1/2,土3/2 B. 土1,土2,土3,土6 C. ±1/2,+3/2 D. ½ 45. One of the roots of the polynomial equation 3x + x - 8x + 4 =0 is -2. Find the other roots? A. 1 and 4 B. 1 and 2/3 C. C.-1 and 3/2 D. 2 and -1/3

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A: suppose

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A:

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A: Solution is given below:

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A:

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A: 1 is the zero of given polynomial.

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A:

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A: Let's find.

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A:

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A:

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A:

Q: 2. Determine the polynomial equation with integral coefficients whose roots are -1, -2, and -3.

A: Answer and explanation is given below

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A: We have to find polynomial

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A: This question is related to polynomials, we will solve it using given information.

Q: 4) -3, -4, 5 ansurer -2 -3 3 answer 6) - answer .

A:

Q: 7. 3/2, -2, 1/3. -1 8. -2/3, -1/2, 2. -5, 1 9.-2. 5/2. 1/3, -3, 2

A: Since the student has posted many sub-parts of the question and does not mention any specific part,…

Q: 42. What is the polynomial equation whose roots are {-2, 2, and 4 of multiplicity 2} A. 2x* - 2x +…

A: As per bartleby guidelines we only give first question answers.

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Q: does there exist a polynomial of degree 3 with real coefficients that has zeros 1, -1, and i?

A: Consider the given roots. 1,-1, i and -i for complex roots. Now, make the polynomial.…

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Q: #7: For what value of k will the polynomial function f(x)=x'+6x² +kx=4 have the same remainder when…

A: The Polynomial Remainder theorem states that if x-b divides the polynomial, Qx, then the remainder…

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A:

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A:

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Q: Find a polynomial f(x) of degree 4 that has the following zeros: 4,-9,-5,0. Leave your answer in…

A: Find a polynomial f(x) of degree 4 that has the following zeros: 4,-9,-5,0. Leave your answer in…