4242 Problem 2 - Independent Practice. Solve for one variable by substitution and plu back in to solve for the other variable. (Double check your answer). 4X=2x+4 (40-8 2x + 16 = -8 85-8 a. x = 2y + 4 4y - 8=x C. -3x+9= 4y x=y=3 y=8x₂ Y=8(1) X=-=8x²8 88 -X=- - 3x + 4 = 4 x (9-3 3XX 9+4 = -3 b. y=-z 5z + 5y = d. 1 2 2y + y=42-1

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.7: Puzzle Problems
Problem 32P
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I need help on substitution x = 2y + 4 and 4y - 8 = x

(-3-22)
Problem 2- Independent Practice. Solve for one variable by substitution and plug the answer
back in to solve for the other variable. (Double check your answer).
4X=2x+4 (40)
1-ho so
2x + 16 = -8
¥8:-8
88
[x = 8)
a.
x = 2y + 4
4y - 8 = x
C.
-3x+9 = 4y
x=y-3
Y=8x
Y=8(1)
-2016
to no
NEJE
12/12 (3)
4242
y=-8
-3x+9=4x (0-3
3X + 9+4 =-3
b.
2
y=-z
5x + 5y=10
2y +4
y=42-1
Transcribed Image Text:(-3-22) Problem 2- Independent Practice. Solve for one variable by substitution and plug the answer back in to solve for the other variable. (Double check your answer). 4X=2x+4 (40) 1-ho so 2x + 16 = -8 ¥8:-8 88 [x = 8) a. x = 2y + 4 4y - 8 = x C. -3x+9 = 4y x=y-3 Y=8x Y=8(1) -2016 to no NEJE 12/12 (3) 4242 y=-8 -3x+9=4x (0-3 3X + 9+4 =-3 b. 2 y=-z 5x + 5y=10 2y +4 y=42-1
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