(-4)2k+1 k3k-2 (x – 2)k 5. Consider the power series >) k=1 (a) Find the radius and the interval of convergence of the series. (b) Consider the function f (x) = (-4)2k+1 k3k-2 2)*, k=1 defined for all x in the interval of convergence. Find f(n)(2) for all n > 0, and find a power series representation for an antiderivative of f(x).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 72E
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(-4)2k+1
k3k-2
5.
Consider the power series >,
-(x – 2)*.
k=1
(a)
Find the radius and the interval of convergence of the series.
(b)
Consider the function
f (x) =
(-4)2k+1
-(x – 2)*,
k3k-2
k=1
defined for all x in the interval of convergence. Find f(") (2) for all n > 0, and find a power series
representation for an antiderivative of f(x).
Transcribed Image Text:(-4)2k+1 k3k-2 5. Consider the power series >, -(x – 2)*. k=1 (a) Find the radius and the interval of convergence of the series. (b) Consider the function f (x) = (-4)2k+1 -(x – 2)*, k3k-2 k=1 defined for all x in the interval of convergence. Find f(") (2) for all n > 0, and find a power series representation for an antiderivative of f(x).
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