46. (a) Find the speed of the particle at time = 2 Find the time when the vertical acceleration of the particle changes from down to up.

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Solve 46 (a) Only in 20 min plz i need urgently plz I will give you thumb up so plz solve in 20 min plz
A particle is moving along a curve such that its speed at time t is (x (1), y(t)). where x (1) = cos² (21)
and y(t) = t + 5. Both x and y are measured in feet per second.
46. (a) Find the speed of the particle at time = 2 Find the time when the vertical acceleration of the
particle changes from down to up.
47. (b) Find the distance traveled by the particle from time t= 1 seconds and
= 3 seconds.
48. (c) Given that the particle's position in the y direction is 4 feet at time = 2 seconds, find the
equation for the position of the particle in the y direction and call it Y(t).
49. (d) Find the acceleration vector at time = 1 seconds.
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Transcribed Image Text:A particle is moving along a curve such that its speed at time t is (x (1), y(t)). where x (1) = cos² (21) and y(t) = t + 5. Both x and y are measured in feet per second. 46. (a) Find the speed of the particle at time = 2 Find the time when the vertical acceleration of the particle changes from down to up. 47. (b) Find the distance traveled by the particle from time t= 1 seconds and = 3 seconds. 48. (c) Given that the particle's position in the y direction is 4 feet at time = 2 seconds, find the equation for the position of the particle in the y direction and call it Y(t). 49. (d) Find the acceleration vector at time = 1 seconds. -
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