468 CHAPTER 14 The Fourier Integral end TransforAS sin(x) for -4sx<0 4. f(x)={cos(x) for 0 4 5. S(x)= * for-100 srs100 0 for jx) > 100 10 11

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.5: Properties Of Logarithms
Problem 68E
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468
CHAPTER 14 The Fourier Integral End Transforms
sin(x) for-4sxs0
4. f(x)={cos(x) for 0 <x<4
1/2 for-5<x<1
8. f(x) ={1
for 1<x<5
for |x) > 4
for |x > 5
for-100 sxs100
0 for [x] > 100
9. f(x)=e-
10. f(x)= xe
11. Show that the Fourier integral of S(x)
5. S(x)=
6. f(x) =
[1x for- Sx< 2n
sin(@(1-x
Tim
for x<-n and for x> 2n
sin(x) for -3t <x<A
7. f(x)=-
for x<-37 and for x>A
Transcribed Image Text:468 CHAPTER 14 The Fourier Integral End Transforms sin(x) for-4sxs0 4. f(x)={cos(x) for 0 <x<4 1/2 for-5<x<1 8. f(x) ={1 for 1<x<5 for |x) > 4 for |x > 5 for-100 sxs100 0 for [x] > 100 9. f(x)=e- 10. f(x)= xe 11. Show that the Fourier integral of S(x) 5. S(x)= 6. f(x) = [1x for- Sx< 2n sin(@(1-x Tim for x<-n and for x> 2n sin(x) for -3t <x<A 7. f(x)=- for x<-37 and for x>A
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