48 Find the equation in standard form for the circle whose diameter has an endpoint at (3, -4) and the origin. 4 x 2 + 4 y 2 + 12 x + 16 y = 0 4 x 2 + 4 y 2 - 12 x - 16 y = 0 4 x 2 + 4 y 2 + 12 x - 16 y = 0 4 x 2 + 4 y 2 - 12 x + 16 y = 0

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