49-2 sin(8) = Video Example 4 EXAMPLE 1 SOLUTION Evaluate |v √49-x² x² Let x = 7 sin(e), where -7/2 ≤ 0 ≤ π/2. Then dx = 49x2 x² |V4 49 - x² = V 49 - 49 sin²(0) = √ 49 cos² (0) = 7|cos(0)| = 7 cos(0). (Note that cos(0) ≥ 0 because dx. -1 dx = -л/2 ≤ 0 ≤ л/2.) Thus the Inverse Substitution Rule gives 7 cos(0) 49 sin²(0) cos²(0) = [cot²(e) de = [(csc²(0). - 1) de de + C. de and de

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