how do i verify my answer for V0 using tellegens theoerm? 1.4 mA (↑)it a mIkaIka{ILANOOT4MAlkn ² Is2k22mAEdelivered+w00-11-47 V₁=0.211O12 V₂=16.4V0 3-2-4 V₁-1.6V @ 1mA + V₂ - V₁ + V₁ V₂₁ V₂ V₂ = 0L-2 -1 -2 5 2 √√√4=441IkIk2k-2kV₁- IKV₂-2V₂ +5V4 = 2mV₁= V₁ = 1.6VOF(2A) Ⓒ2kaa Mode AnalysisS2kakⒸV₁ + V₁ - V₁ + 4m = 0IL+ @ -4m + V₂-V₁-2m=02.k12V/₂-1k V₁ = 12 mIL2LV₁-V₁-4mA€+32k Vo2m + V₂ Vy+ V₂ = 012 2k3KV₂-2V4 = -4mb) keep AnalysisⒸlk (1-4)+x+ lk (1₂) = 02k1₂-4V+x=0Ⓒlk (T+ + 2m) + 2k (Tu) - X=032 +2V-X=62k13 +3k 14-2V=O2k1s+ 6V+3k]s=2V=05kI3 = -4V5k5k1₂=-0.2mA14-1= Im14 = m + 13I4 = 1m+-0.2mI4 = 0.8mV. Luk.= 0.8m (2k)= 1.6V

Given Data: A DC circuit with known values of, Node voltages Mesh currents Tellegan's Theorem: It…

4mA ↑ Ⓒ ins lka ka 12 222mA m 4A) A lkn = I₂ Eselivered 00 -47 V₁=0.20 10 -112V/₂=16.4V 2 O O 03-2-4 V₁=16V @ -1 mA + V₂ - V₁ + L-2 -1 -2 5/2 √√√4=441 Ik V₁= V₁ = 1.6V (√₂ = @Made Abralysis ⒸY₁+ V₁ - V₁₂+ 4m = 0 TL TE ZIV₁-V₁=-4mA 2ka IMA 4 kak @-4m+V₂-V₁-2m=0 2.k 12V/₂-1k V₂ = 12 m 32m + V₂-V₁ + V₂ =0 16 2k 3kV₂-2V/4= -4m. + 1₂ 3¹ Vo ه - ولا ولا خلا ولا Ik -2kV₁- IKV₂-2V₂ +5V₂ = 2m 2k b) kop Analysis Ⓒlk (1-4) + x + lk (1₂) = 0 2k1₂-4V+x=0 ⒸIKCT+2m) + 2k (Tu)-X-0 32 14 +2V-X=6 2ks +3k 14-2V=0 2k1₂ + 6V +3kIs-2V=0 5kI3=-4V 51 5k Is=-0.2mA 14-1= Im 14 = m + 13 I4 = 1m+-0. 14 = 0.8m V.-IR. = 0.8m (2k) = 1.6V

4mA ↑ Ⓒ ins lka ka 12 222mA m 4A) A lkn = I₂ Eselivered 00 -47 V₁=0.20 10 -112V/₂=16.4V 2 O O 03-2-4 V₁=16V @ -1 mA + V₂ - V₁ + L-2 -1 -2 5/2 √√√4=441 Ik V₁= V₁ = 1.6V (√₂ = @Made Abralysis ⒸY₁+ V₁ - V₁₂+ 4m = 0 TL TE ZIV₁-V₁=-4mA 2ka IMA 4 kak @-4m+V₂-V₁-2m=0 2.k 12V/₂-1k V₂ = 12 m 32m + V₂-V₁ + V₂ =0 16 2k 3kV₂-2V/4= -4m. + 1₂ 3¹ Vo ه - ولا ولا خلا ولا Ik -2kV₁- IKV₂-2V₂ +5V₂ = 2m 2k b) kop Analysis Ⓒlk (1-4) + x + lk (1₂) = 0 2k1₂-4V+x=0 ⒸIKCT+2m) + 2k (Tu)-X-0 32 14 +2V-X=6 2ks +3k 14-2V=0 2k1₂ + 6V +3kIs-2V=0 5kI3=-4V 51 5k Is=-0.2mA 14-1= Im 14 = m + 13 I4 = 1m+-0. 14 = 0.8m V.-IR. = 0.8m (2k) = 1.6V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Is=1A Is= 20 degrees R= 1050ohm X1=1100ohm X2=600ohm X3=500
How can I find the solutions for this problem? (answers are given) Answers: a.i. Eth = 4 V, Rth = 3.857 ohmsa.ii. Eth = 15 V, Rth = 3.214 ohmsb.i. IN = 1.037 A, RN = 3.857 ohmsb.ii. IN = 4.667 A, RN = 3.214 ohms
Give solution/explanation for letter i only. Answer Capacitive, 8.4883?FSubquestion/s are given with their corresponding answers. A pure element is connected across an AC signal. CH1 and CH2 measures the voltage and current respectively:CH1 (Yellow) SettingsVolts/Div: 50VTime/Div: 5msProbe Settings: X1CH2 (Blue) SettingsCurrent Probe Ratio: 100 mV/mAVolts/Div: 20VTime/Div: 5msProbe Settings: X1If ?? (distance between two ‘purple’ cursors) is 5ms, determine:a. Periodb. Frequencyc. Phase Angle Differenced. CH1 Peak Voltagee. CH1 RMS Voltagef. CH2 Peak Currentg. CH2 RMS Currenth. Impedance of the pure elementi. Type of load. If reactive, indicate the values of inductance or capacitance a. 20 msb. 50 Hzc. 90°d. 150 Ve. 106.066 Vf. 400 mAg. 282.8437 mAh. 375 Ωi. Capacitive, 8.4883?
Urgent!! Please write down all workings thank you! Answer: V1 = 0.928cos (10t - 86.142deg) mV V2 = 0.969cos (10t - 16.48deg) mV I1 = 2.5 cos 10t mA I2 = 1.5cos(10t -42deg) mA I3 = 0.484 cos (10t - 16.48deg) mA
HEY PLEASE HELP ME BELOW V1 = 8 cos (ωt − 25◦)I2 = 10 sin (ωt − [-111◦])By how many degrees is I2 leading V1? (Give your answer θ in the range from −180◦ to 180◦ I GOT 4DEGREES BUT I'M NOT SURE ABOUT IT.
SOLVE FOR i_x AND v_x(NEED A NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE)
Solve for the I1 and I2. Answer in polar form and round off answers to 5 decimal places. Clue: I1 is near 608.74, -43.65 degrees, I2 is near 632.98, -18.43 degrees
How can I get the solution for this problem? (answers are given) Answers: a.i. Eth = 14 V, Rth = 2 ohmsa.ii. Eth = 19 V, Rth = 1.5 ohmsb.i. IN = 7 A, RN = 2 ohmsb.ii. IN = 12.667 A, RN = 1.5 ohms
note: please use the attached format to solve homework question, previous solution has been marked wrong which you have solved last time. Homework-1: A device has been tested under different load conditions and load currents have been recorded. Using appropriate techniques, combine the following recorded currents into one single wave i. I1= 0.866SinƟ+0.5CosƟii. I2= 0.574SinƟ-0.819CosƟiii. I3= 0.866CosƟ-0.5SinƟ
Please answer ASAP for like this please answer ASAP for like this please.. It's urgent.
Find Io and current at point x. Use A. KVL (include and draw the direction of loops) B. KCL (include and draw the direction of each current) S1= 30 S2= 220 f= 60 hz R1= 8 R2= 7 R3= 15 R4= 28 L1= 0.06 H C1= 0.2 mF note: Zl= R3
Find Req . Using wye-delta Transformation . The answer is .( Req= 28.5 ) I know the answer but please make the steps clear and the diagrams clear . Thank u Please answer in typing format please ASAP for