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-4x -2 y' = (x2+1)(2x) answer %3D (x² +1) Exercises: Evaluate the following and simplify theresult whenever possible 5. y = Ta :- arc sin= 6. y = x?arc cos

-4x -2 y' = (x2+1)(2x) answer %3D (x² +1) Exercises: Evaluate the following and simplify theresult whenever possible 5. y = Ta :- arc sin= 6. y = x?arc cos

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.10: Partial Fractions
Problem 12E
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(x2 – 1)(2x) – (x² + 1)(2x) (x² – 1)2 y': x2 + 1 (x2 + 1)2 — (х2 — 1)2 (x² – 1)² x2 2x(x² – 1 – x² – 1) (x2 - 1)2 x2 +1 x4 + 2x2 + 1- x4 + 2x2 – 1 х2 — 1 у (x2 – 1)2 -4x 4x2 x2 – 1v (x2 – 1)2 x² + 1 (x2 – 1)2 . -4x -2 y' (x²+1)(2x) %3D answer (x² +1) Exercises: Evaluate the following and simplify theresult whenever possible х 5. y = Taž-x 6. у 3D х*arc cos arc sin- 7. y"of y = arc tan3x? 8. y"of y = arc cosx? 9. y"of y = arc sin(2x - 3) 10. y"of y = arc tan
Transcribed Image Text:(x2 – 1)(2x) – (x² + 1)(2x) (x² – 1)2 y': x2 + 1 (x2 + 1)2 — (х2 — 1)2 (x² – 1)² x2 2x(x² – 1 – x² – 1) (x2 - 1)2 x2 +1 x4 + 2x2 + 1- x4 + 2x2 – 1 х2 — 1 у (x2 – 1)2 -4x 4x2 x2 – 1v (x2 – 1)2 x² + 1 (x2 – 1)2 . -4x -2 y' (x²+1)(2x) %3D answer (x² +1) Exercises: Evaluate the following and simplify theresult whenever possible х 5. y = Taž-x 6. у 3D х*arc cos arc sin- 7. y"of y = arc tan3x? 8. y"of y = arc cosx? 9. y"of y = arc sin(2x - 3) 10. y"of y = arc tan
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