Convert ∫50∫25−y2√0∫50−x2−y2√x2+y2√(x2+y2+z2)dzdxdy∫05∫025−y2∫x2+y250−x2−y2(x2+y2+z2)dzdxdy into spherical coordinates. /25-y²50-T" (z² + y° + =*)dzdzdy into spherical cordinates.Convert• 27/3ρ' cos φdρdφdθ-7/2 .• 5/2p* sin ødpdodo7/2-/2 Jo7/4•7/25•7/47/2 5/2pª sin ødpdødeT/3/2p* sin ødpdodø• 7/2 p5/2p* sin ødpdodø•7/2p cos ødpdodo-7/2 Jo

Answer:We have to convert∫50∫25-y20∫50-x2-y2x2+y2x2+y2+z2 dzdxdy into sphercal coordinates∵0≤y≤5…

5 25- y² 50-g² –y² Convert (x² + y² + z²)dzdædy into spherical coordinates. ²+y² 5/2 pª cos ødpdød0 • 27/3 • T/2 -7/2 Jo 5/2 ρ' sin φdρdθdφ -7/2 Jo • T/4 T/2 • 7/3 (/2 p5/2 ρ' sin φdρdθdφ 7/4 /2 sin ødpdodø » 5/2 pª cos ødpdodo -T/2 Jo

5 25- y² 50-g² –y² Convert (x² + y² + z²)dzdædy into spherical coordinates. ²+y² 5/2 pª cos ødpdød0 • 27/3 • T/2 -7/2 Jo 5/2 ρ' sin φdρdθdφ -7/2 Jo • T/4 T/2 • 7/3 (/2 p5/2 ρ' sin φdρdθdφ 7/4 /2 sin ødpdodø » 5/2 pª cos ødpdodo -T/2 Jo

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

Convert ∫50∫25−y2√0∫50−x2−y2√x2+y2√(x2+y2+z2)dzdxdy∫05∫025−y2∫x2+y250−x2−y2(x2+y2+z2)dzdxdy into spherical coordinates.

/25-y²
50-
T" (z² + y° + =*)dzdzdy into spherical cordinates.
Convert
• 27/3
ρ' cos φdρdφdθ
-7/2 .
• 5/2
p* sin ødpdodo
7/2
-/2 Jo
7/4
•7/2
5
•7/4
7/2 5/2
pª sin ødpdøde
T/3
/2
p* sin ødpdodø
• 7/2 p5/2
p* sin ødpdodø
•7/2
p cos ødpdodo
-7/2 Jo

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