5-5cos 0 8) lim 0-0 sin 70

Q: Establish each identity.

A:

Q: Find the limit.

A: Given: Now using the properties of limit:

Q: 12 tan(0) = find sec(0) 12

A: sec(theta)=? cos(theta) = ?

Q: sin (7π/6) + cos (3π/2)

A: Given,

Q: 11 csc2 (-0) tan 0 cot(-0) Establish the identity: - sec2 e

A: Given,

Q: tan 0 7. lim 0→0 sin 20

A: We will solve the problem by evaluating the limit.   NOTE :: As per our guidelines we are supposed…

Q: *2/3 tanx sec*x dx. Use trigonometric group

A:

Q: Find the limit.

A: Consider the given limit lim△x→0sinπ6+△x-12△x   Use the formula  sinx+y=sin x cos y+cos x sin y…

Q: 1- sin0 lim а) 1+ cos 20 2

A:

Q: 2 1. sin 0 == and sec 0 > 0 2. sece = - and tan 0 > 0 3

A:

Q: 21 and tan(0) 29 21 find sec(0). 20 If sin(0)

A: To.find - Value of sec theta.

Q: - Ix-4 5. lim 1 3x² +5x+2 6. lim 14 x -x-12 tan 0 cos 20 7. lim 0–→0 sin 20 8. lim 0→n/2 tan0

A:

Q: sin(1+ cos(0)) Find lim 1+ cos(0) Select one: О a. -1 O b. 1 Oc-2 O d. 2

A:

Q: 1-cos(2x) sin²(3x) tan x-sin x Evaluate: a- limr-0* b- lim sin³x

A: (a) Given, Simply fie the above expression, On applying the limit, the solution is in 0/0 format.…

Q: 9. lim Va sin -00

A: we have to use L'hospital rule to find limits

Q: Infinite limits at infinity Determine the following limits.

A:

Q: tan 2x 5. lim→0 sin 5¤

A:

Q: Evaluate the limit.

A: limt→01-cos2tsin23t

Q: 2/2 and <x< 3 Зл find tan 2x. 2' 4. If sin x

A:

Q: 1-cos(2x) - Evaluate: a- lim,-0 sin²(3x) tan x-sin x b- lim sin3x

A: According to L'hopitals rule,limx→af(x)g(x)= limx→af'(x)g'(x)iff(x)g(x)= 00or ∞∞. If there is any…

Q: cos² (1 – cos?(1 – cos² (1...cos² 0)).....) cos“ (1...cos´ 0)).....) - - Evaluate lim TT (/0 + 4 sin…

A: Introduction :

Q: 5 cos 20-5 lim 40 0→0

A:

Q: Find the limit

A: First write tan and cot using sin and cos

Q: 5 sin coso do 2 Sin ² + 3 sin 0 -4

A:

Q: tane 12. lim 80 sin20

A: First of all substitute the value of the limit that is 0 in place of θ in the function.…

Q: The value of sin(3x) 7. lim it sin 2 is

A: Since you have posted multiple questions, as per our policy we will answer first question. Please…

Q: 1. If tan x = -3 then tan (-x) =  2. If sin x = 0.3 then sin (-x) = 3. If cos x = 0.2 then cos (-x)…

A: Answer 1. We know that  sin(-x)=- sinx and cos(-x)= cos x  tan x= sin xcos xHence  tan (-x)= sin(-…

Q: 1 5. Find lim 2+sin 0 2 sin 0

A:

Q: If tan a = - 1 then tan( – x) = If sin æ = 0.4 then sin( – æ) = If cos z = 0.5 then cos( – 2)= If…

A:

Q: 1. If tan x=1 then tan(−x)=    2. If sin x=0.2then sin(−x) =    3. If cos x=0.6 then cos(−x)=…

A:

Q: 1-sin 0. (5) lim cos.20 (x2-2х+1)50 (6) lim X-00 (х+5)100

A:

Q: 2.6 Show that if J sin ! if 0 < x <1, if x = 0, f(x) = then lim,-0+f(x) does not exist. (See Fig.…

A:

Q: Prove limθ→0 sin (θ)/θ=1.

A:

Q: sin 30 25. lim 0→0 tan 20

A: Evaluate the given limit.

Q: 9. tan 0 = 4, sin 0 < 0 %3D

A: As per Bartley guidelines we are supposed to answer only one question per post. This post contains…

Q: 0(1+ cos 0) 5 ) lim 0-0 sin 0 cos 0 -li

A:

Q: 1. If tan a = - 3.5 then tan( – 2) = 2. If sin æ = 0.4 then sin( – æ) = 3. If cos x = 0.9 then cos(…

A: 1.  tan is negative in 4th quadrant tan(-x)=-tanx= 3.5 2. sin is negative in 4th quadrant…

Q: tan 6+ sin 0 cos 2 2 tan e

A:

Q: lim Cos (40)-1 846 Sin (18)

A: NOTE: Refresh your page if you can't see any equations. . use L'Hopital's rule

Q: lim 0-0 cos(90) tan(90)

A: ⁹

Q: (1-cos(x))= (2-2sin^2(x)) from (-pi, pi)

A:

Q: sin 3x 39.lim tan 6t 41. lim 50 sin 21

A: We will use the l'hospital rule to fine the limit of 39.  To fine limit 41. We will use the basic…

Q: Find the limit

A:

Q: у" + 9у %3D tan(3x)sin(3x); У (0) %3D 1, у' (0) %3D 2

A:

Q: 1. Evaluate 2. Evaluate sin(20) 30 x-2x cos x sin x limo lim, 0

A: Given is  limθ→0sin(2θ)3θ. L'Hospital rule: limx→af(x)g(x)=limx→af'(x)g'(x) NOTE: According to the…

Q: 7. tan x + sec 3 =

A: Given:

Q: sin 20 7. lim n sin 0 tan 0 6.

A: We can solve it using the properties of limit as below

Q: 1-cos 40 lim 00 1-cos 6O Evaluate : -

A:

Q: #44

A: To determine the value of the required limit