5 panels at 3 m E 3 m G 1.8 kN 15 1.8 kN 3 m 15° 3 m 5 m

Q: Q/ Find the force just in members BD, CD and CE? 3 m 4 m 3 m 3m 3 m 3 m 3 m 30 kN 30 kN 90 kN

A:

Q: 2m A * 4m 4m E 4M 4200 kN

A:

Q: 1. Please find the support reactions at A and 5 kN 20 kN В. 30° 1m 1m 1m

A:

Q: I kN 2 kN 2 kN 2 KN I kN H D46 m D 2,62 m E 24 m24 m 24 m24 m Cigur

A:

Q: E 1 m 3 kN/m B G I m F -1 m→ -1 m- 1 2 m

A: Consider the Beam BC as shown below, VB+VG=3×1+1+1+1VB+VG=12    ....... (1)Taking moment about…

Q: Q/ The force in the member (CA) is 12m 50 ку. 10 points 5m 16x

A:

Q: E 4 ft G B D 12 kip 4 ft A 4 ft 4 ft 4 ft- -

A: A truss is a structural member, used to create rigid structures. The main function of the truss is…

Q: -5 ft 3 ft- 2 ft 4 ft B В 5 3 12 13 4 5 500 lb 200 lb 260 lb

A:

Q: 50 KN/m 120 KN.m B- 9m 4m

A: For solution refer below images.

Q: 40 kN E 2 m B F 3 m 50

A: to find reaction component at B and C

Q: 9. The moment of force F [Ib.ft] about Xaxis: a) 10 b) 11 c) 14 d) 8 e) None

A:

Q: free-body diagrams. 6 ft 3 kip/ft B. 2 kip/ft -3 ft C

A: As per bartleby guidelines we are allowed to solve only 1st question if multiple questions are…

Q: 15 kN 10 kN 12 kN/m 8 kN/m A C. D 3 m 2 m 3 m El is constant

A: configuration diagram:

Q: F1 = 5 kN F2 = 13 kN 0 = 45° B - 60° C F3 = 4 kN B 2 m 3. 7m F4 = 22 kN E lJa = 30° F5 = 4 kN

A: In case of multiple force on a system, resolve the forces in horizontal and vertical direction. This…

Q: G 1 m H 2 m |C -2 m 2 m -2 m- -2 m 10 kN 15 kN 30 kN

A: Calculate the reaction at the support, RA+RE=10+30+15RA+RE=55   ....... (1)Taking moment about…

Q: View Policies Current Attempt in Progress Calculate the moment (positive if counterclockwise,…

A: Given data: The applied force, F=180 N. Resolve the applied force in the vertical component and…

Q: a. 24 kN 3 m 7 kN/m B 90 kN-m 6 m V max M max 3m D 3 m 12 kN X E

A: First calculate the reactions the. Draw the sfd and bmd

Q: F1 = 5 kN F2 13 kN -30 C. F3 = 4 kN 45 A 2m 7 m 5n F4 = 22 kN a30° F5 = 4 kN

A:

Q: W=4 kN/m 5 kN A 2.5 m + 1.5 m

A:

Q: 6 ft y 9 + B E 4 ft- D H -4 ft 4 ft K +ft- G 3000 lb 1000 lb X

A: Given: Force applied at point H: →FH=3000 lb    (in downward direction) Force applied at point G:…

Q: 20 kN 12 kN A В M = 10 kN-m %3D 4m 4m 4m Figure Q1 (b)

A:

Q: Find the force of the rods AB, AC, BC and BD. 20 N 30 N В 4m 4m 4m 4m 4m 4m A 4m E

A:

Q: F B 4 m 4 m 4 m 4 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: A P3 3 m B F P₁₁ -3m- E C P₂ -3m- 3 m D

A:

Q: H L 3 m A G F - 2 m-| B C D +2 m-+2 m+ 2 m--2 m+2 m +2 m- 4 kN 5 kN 6 kN 8 kN

A:

Q: 15 kN 10 kN/m 20 kN · m A 2 m 1m 1m 2 m What is the reaction force at A?

A: Given: Point load=15kN Moment=20kNm Uniform load=10kN/m

Q: 8 kN 6 kN/m А С 1m 4 m 3 m m E.

A: Calculating the reaction at the support,

Q: A 2 ft F, 4 ft M B. - 3 ft- 30 -x F,

A: Given that, F1=150 lb,F2=50 lbM=500 lb.ft Consider the given frame, Resolve the given force in two…

Q: C ... 2 kN 1.5 m D 0.8 m В A E |H |G F -1 m V1.5 kN 1 m 2 m- -2 m

A: GIVEN PIN JOINTED TRUSS WE HAVE TO FIND FORCES IN GIVEN MEMBER

Q: F = 120 lb | 30° 12 kN 1.25"- 30 4 m 1.5" 5 m 11"

A:

Q: 120 kN 7.5 kN/m 417.5 kNm 282.5 kNm A C +5m→5 m 10 m - RA = 115.5 kN Rg = 79.5 kN

A:

Q: gure |2P Pro A |B -2 ft2 ft - –2 ft d 2 in.

A: For solution refer images.

Q: 15 kN 30 kN-m Figure 2 ID в 1.5 m 3 m 1.5 m

A: The fixed support resists all the moments that is translational motion and the rotational motion of…

Q: 125 kN 50 kN/m VIIE A C 3 m 12 m

A:

Q: 120 kN 7.5 kN/m 417.5 kNm 282.5 kNm A D 5 m 5 m 10 m- RA = 115.5 kN Rg = 79.5 kN

A: Shear force diagram represents shear force at every section of the beam. Shear force at any…

Q: 6500 N - 4.5 m– 4.5 m A 1.5 m D 2 m E B

A:

Q: 100 kN Half circle 6.0 m Pinned Pinned 4.0 m 40m

A: Let RA and RB are the reactions at pin support  By law of equilibrium of forces in vertical…

Q: -5 at 3 m = 15 m- 12 kN 12 kKN |M IN 12 kN 12 kN 12 kN 12 kN L 20 kN– 4 m 40 kN- G 4 m 40 kN- 4 m 40…

A: The free-body diagram of the structure is shown as

Q: NOT TO SCALE G H F 6 m 11 m E B D 4 kN 10 kN 7 kN 6 4 @ m-

A: The free body diagram of teurs is : ∑MA=0 => FE (20) - 10(6)- 7 (10)- 4(15)=0…

Q: (4) 18 kN 4 kN/m B 6 m -2 m

A: Question 4) is a propped cantilever beam

Q: B 3 m E - 3 m - 3 m - 3 m · 10 kN 15 kN

A: Calculate the reaction at the support, VA+VF=10+15VA+VF=25 kN   ................ (1)Taking moment…

Q: 8 kN 25 kN-m 2 m- 2 m -2 m 5 kN Fig (1)

A:

Q: 5 kN/m 5 kN/m -4.5 m- -4.5 m

A: given; AC=4.5m CB=4.5m AB=9m lets take reaction force at B=RBlets take reaction force at B=RA weight…

Q: 3. Solve for EG, GH, and HJ 1 kN 2 kN 2 kN 2 kN 1 kN H 0.46 m F D 2. 62 m B A E| 2.4 m 2.4 m 2.4 m…

A:

Q: 30° 600 lb 20° 5 ft Prob. F4-5 300000 pom 0.5 ft

A:

Q: 100 kN I 120 kN/m 60 kN/m Ic D 315 kN-m 3 m 3 m 3 m 3 m

A: Draw the free-body diagram of the beam.

Q: 20 kN 40 kN/m Al C 150 KN•M 8 m- - 3 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: E 2.10 m A B D -1.65 m- -1.65 m- 1.65 m- 10.0 kN 12.0 kN

A:

Q: Determine the forces in members FH, GH, and GI of the roof truss shown.

A: The reaction at A and L is calculated as : RA+RL=1+1+1+1+1+5+5+5=20…

Basic Terminology in Mechanics

The area of science and mathematics concerned the motion of the objects, the relation between the force matter, and motion if specified. Forces exerted over the objects result in displacements or changes in the position of an object concerning its environment. This branch of physics keeps its roots in Ancient Greece in the form of the scripts of Aristotle and Archimedes.