5 s² – 15s – 11 F(s) = s°(s² + 1)

Q: Solution: [11 Consider, 3 2 Differentiate with respect to 't we 2. - 3 2. dluv) = udv +vdu to Land.…

A: The given equation is x3-3x2y=c

Q: An object is moving along a horizontal path with its position modeled by the equation (t) =t³ – 2t2…

A: Given: xt=t3-2t2-3t for finding position at t=1, we put t=1 in given position expression so,…

Q: 6. Find the position function of a particle moving along a coordinate line whose velocity at time t…

A: The velocity of the particle is given as a function of time by, v=6t2-4t+4 The velocity of a…

Q: f(t)-[te-" sin 3(t - t) dr 3 3 (s+2)°(s² +9) (s– 2)°(s² +9) O A.) В.) - 6s (s +2)(s² +9)² - 6s (s –…

A:

Q: a. Solve the following. 1. Find the angle of intersection between the curves y = Vx and y = 2 – x².…

A:

Q: Q#2. A heat-seeking particle is located at the point (2,3) on a flat metal plate whose temperature…

A:

Q: = 2t + 4e2t + cos(t) and initial position s(0) = 4. Find A particle moves in a straight line with…

A:

Q: 1 F(s) = ;L-1{F(s)} =? (s+1)(s²+1) elect the correctresponse: o f(t) = -e-t +te-t+e* %3D NONE OF…

A:

Q: dy We wish to find the solution to = x®y that passes through the poin dæ (x, y) = (1, 3).

A:

Q: 9. The equation of motion of a train is given dv by: m=mk(1-e)- mcv, where v is the dt speed, t is…

A:

Q: (3) Find the position function of the particle at time t ≥0. a(t) = 3t −14, v(2) = 0, s(−1) = 2

A:

Q: Using a(t) = (d2s/dt2) = -4 sin 2t, v(0) = 2, s(0) = -3 find the body's position at time t.

A:

Q: f (x) = 5.6 sin (2.6x – 4.2) – 9.1- What is the equation of the midline of the function %3D o y =…

A:

Q: Question 2 Find the general solution of y" + xy' – y = 1 using variation of parameter with y1 = x

A: Consider the given equation: Here, y'' + xy' -y = 1        ......(1)

Q: S(t)=t°-3tー+5 find accelercstuon of the purticle at t=1.

A: Here s(t)=t6-3t2+5 We have to find the acceleration at t=1.

Q: The velocity of a particle moving along the x-axis is v(t)=3t+2.At t = 0, its position is 3.  What…

A: The velocity of the particle is vt=3t+2. Evaluate the position of the particle as follows.…

Q: Q.5 Consider the Sturm-Liouville problem d -(xy')+(2-1)y=0, dx y'(1)=0, y'(e²)=0

A: Given,           xddxxy'+λ-1y=0,    y'(1)=0, y'(e2)=0.

Q: 3. * c0.5 Evaluate I= °(x² + 8)dx using two points by Gaussian quadrature O 4.01 - 4.02 4.02 - 4.03…

A: Given : I = ∫00.5x2 + 8 dx   To evaluate I = ∫00.5x2 + 8 dx using two point Gaussian quadrature.

Q: 2. f(t) = -7(e^3t)[sinh(2t)] A. -14 / (s^2 – 6s + 5) B. (-7s + 21) / (s^2 – 6s + 5) C. -14 / (s^2 -…

A:

Q: position of a moving object is s (t) = 1³ – 31² - 45t-1. What is its acceleration at t=2?

A: Given query is to find the acceleration at indicated point.

Q: Solve the problem. Given the velocity and initial position of a body moving along a coordinate line…

A: Given that velocity V(t) = -5t + 5 And initial position S(0) = 14

Q: The position of the particle at time t is given by s(t) = t² – 6t + 8. The particle is moving from…

A: Given:  Position of particle at time t = s(t) = t2 - 6t + 8   To find: Time(t) at which the particle…

Q: (2) A particle moves along the 1-aris such that the velocity is given by v(t) = 20e' +t for t > 0.…

A: Here, the velocity vector is: v(t)=20et+t7

Q: (b) Solve the initial value problem y' = x*(1 – y), y(0) = 3. %3D (c) Find the points on the curve…

A:

Q: A particle moves along a coordinate axis. Its position at time t is given by p(t) = t³ – 3t + 5. Is…

A: The position of particle is given as p(t)=t3-3t+5. We find its velocity by differentiating p(t),…

Q: A particle is moving with acceleration a(t) = 36t + 2. its position at time t = 0 is s(0) = 2 and…

A:

Q: 8. The acceleration of a particle moving along x-axis at time t is defined by a=4t-12. At t=0, the…

A: Given: The acceleration of a particle moving along x‐axis at time t is defined by a=4t-12. At t=0,…

Q: Find ∫C (ez - 1) / z  dz with C being z(t) = eit for 0 ≤ t ≤ 2π

A:

Q: A particle starts at time t-0 and moves along the x-axis so that its position at any time tz 0 is…

A: The position of the particle at any time t is: x(t)=t-132t-3x(t)=2t4-9t3+15t2-11t+3

Q: (D³ – 3D² + 9D + 13)y = 0 Find the solution. y = c,e- +c,e* cos 3x + c,ez" sin 3x y = c,e* + cze*…

A:

Q: The position of the particle at time t is given by s(t) =t- 6t +8. The particle is moving from left…

A: The position of the particle is, s(t) = t² - 6t + 8 So, the velocity of the particle is, v(t) =…

Q: A particle starts at time t=0 and moves along the x-axis so that its position at any time tz 0 is…

A:

Q: A particle is moving with v (t) =t – 3vt. Find the position of the particle at time tif s (4) = 2.

A:

Q: The position of the particle at time t is given by s(t) – t- 16t + 63. The particle is moving from…

A:

Q: What is the annihilator for y=x e*cos 2x ? A (D2-2D+5)2 B (D2+5)2 © D2-2D+5 (D D2 +5

A: A detailed solution is given below.

Q: t -4t +24 - Jydt = e s(t-3) yro) = 0 ,y'co)= o ,y'c0) = 0

A:

Q: 2. You are standing at the point (1,1,3) on the hill whose equation is given by z = 5y – x² – y?. !!…

A:

Q: Prove that: 1st equation = 2nd equation Equation 1 Sn = a + (a+d) + (a+2d) +...+ [a+(n-1)d]…

A:

Q: MS. J., 2.9023, V.03040 +e Using Newton-Raphson -0.2t . 10. The bacteria concentration in reservoir…

A:

Q: A particle moves along a coordinate axis. Its position at time t is given by s(t) = t² - 5t + 1, t >…

A:

Q: (D³+3D²– 4D)y = 0 -4x Question 5 Find the solution. dy 31+9y=2ty 5/3 dt

A: P

Q: 4. Find the length of the curve Vē - 1 dt, y = 1<I< 16.

A:

Q: A particle moves on a coordinate line with acceleration a = d2s/dt2 = 15√t - (3/√t), subject to the…

A: Given that, a=d2sdt2=15t-3t

Q: 2. The position of a particle is i (t) = (2.0or² i+ 6.0j – 6.0t k) m. a. Determine its velocity and…

A: To find Velocity and acceleration vectors from the given position vectors.

Q: What is the annihilator for y=x e*cos 2x ? A D2+5 B D2-2D+5 © (D²-2D+5)2 (D² +5)2

A:

Q: What is the annihilator for y=x e*cos 2x? A (D2+5)2 B D2+5 D2-2D+5 D (D²-2D+5)2

A: Explanation of the answer is as follows

Q: A particle moves along the x-axis in such a way that its acceleration at time t for t ≥ 0 is given…

A: A particle moves along the x-axis in such a way that its acceleration at time t for t ≥ 0 is given…

Q: (s4) 4 (s) - sp [ (s 1)° (-2s) - (L-s³) a (s'+ 1) (2 s) -Rs - ?S - †S + +s3 (s+ 1)3 %3D F(S) Hence,…

A: We need to find Laplace Transform of , f(t)  = t2 cos(t) Since we know ,  F(s) = Lf(t) F(s) = Lt2…