5. If z is any point on the circle |z1 – 2| = 2, then prove that - 2 arg(z – 2) = 2 arg z = arg (z² – 2z). | 3 z²-z 3 6. On |z| = 2, show that Iz4-3z+2| |z3+z²_3| 39 1. On |z| = 3, show that z3+8 19

Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter10: Analytic Geometry
Section10.4: Analytic Proofs
Problem 28E
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5. If z is any point on the circle |z1 – 2| = 2, then prove that
arg(z – 2) = 2 arg z = - arg (z² – 2z).
%3D
2
3
z2-z
3
6. On |z| = 2, show that
%3D
|z4-3z+2|
|z3+z²-3
39
1. On |z| = 3, show that
-
z3+8
19
VI
VI
Transcribed Image Text:5. If z is any point on the circle |z1 – 2| = 2, then prove that arg(z – 2) = 2 arg z = - arg (z² – 2z). %3D 2 3 z2-z 3 6. On |z| = 2, show that %3D |z4-3z+2| |z3+z²-3 39 1. On |z| = 3, show that - z3+8 19 VI VI
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