5. Now compute Average GPA in each class. Display class_code, Class_GPA. Assume all courses are 3 credit courses. A general formula for GPA would be sum(gradepoints x Hrs)/sum(Hrs). Here you can just take an average of gradepoints as the credit hours are same for all courses.
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5. Now compute Average GPA in each class. Display class_code, Class_GPA. Assume all courses are 3 credit courses. A general formula for GPA would be sum(gradepoints x Hrs)/sum(Hrs). Here you can just take an average of gradepoints as the credit hours are same for all courses.
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- You are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. You want to check for postal codes that are greater than 7 characters long. You write the SQL query below. Add a LENGTH function that will return any postal codes that are greater than 7 characters long.You are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. You want to check for postal codes that are greater than 7 characters long. You write the SQL query below. Add a LENGTH function that will return any postal codes that are greater than 7 characters long. 1 SELECT 2 * 3 FROM 4 customer 5 WHERE What is the last name of the customer that appears in row 10 of your query result?Hello, I am wondering why I am getting an error message when I am trying to execute this code in SQL query management. Here is the code: SELECT xxx m.ManagerID, m.MFName, m.MLName, COUNT(b.BuildingID) AS NumberOfBuildingsManagedFROM xxx HAFHMORE.Manager AS mJOIN HAFHMORE.Building AS b ON m.ManagerID = b.ManagerIDGROUP BY m.ManagerID, m.MFName, m.MLNameHAVING COUNT(b.BuildingID) > 1;\ And this is the error: Msg 102, Level 15, State 1, Line 1Incorrect syntax near '.'.
- Let's wa(k through a review of basic SQL syntax, using as an example the database that was mentionedearlier. This database has the following simple structure(* indicates a primary key):Courses: CourseID*, CourseName, TeacherIDTeachers: TeacherID*, TeacherNameStudents; StudentID*, StudentNameStudentCourses: CourseID*, StudentID*Using the above table, implement the following queries.Query 1: Student Enrollment Query 2: Teacher Class SizeYou are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. The state names are abbreviated. You want to check for state names that are greater than 2 characters long. You write the SQL query below. Add a LENGTH function that will return any state names that are greater than 2 characters long.I NEED HELP WITH THIS QUESTION FOR MY DATABASE MANAGEMENT CLASS FOR SQL DEVELOPER In reporting total_sale by each REP including those who made no sale, which Table joins should be left join. And how to show zero in your report instead of null for reps with no sale.
- In the SQL Oracle Application Write one query to return the employee_id, job_id, hire_date, and department_id of all employees and a second query listing employee_id, job_id, start_date, and department_id from the job_history table and combine the results as one single output. Make sure you suppress duplicates in the output.This actually didnt work to resolve my problem... Heres what I have so far. CREATE TABLE Horse ( ID SMALLINT UNSIGNED AUTO_INCREMENT, RegisteredName VARCHAR(15), PRIMARY KEY (ID)); CREATE TABLE Student ( ID SMALLINT UNSIGNED AUTO_INCREMENT, FirstName VARCHAR(20), LastName VARCHAR(30), PRIMARY KEY (ID)); -- Your SQL statements go hereThe Marketing team wants to collect emails of the users on InstantStay. However, the team needs a SQL statement to execute inside their programming environment. You need to create a statement that they can easily run the EXECUTE command to return a single column table containing the USER_EMAIL addresses.
- I need help with understanding how to do the SQL code for the following question (attached is the CSV database file): These are the header titles from the picture: ProductModelName, ProductCategory, ProductPrice, RetailerName, RetailerZip, RetailerCity, RetailerState, ProductOnSale, ManufacturerName, ManufacturerRebate, UserID, UserAge, UserGender, UserOccupation, ReviewRating, ReviewDate, Review Text 1. Get the total number of products reviewed and got Rating 5 in Every CityGiven the following SQL statement, which statement is most accurate?SELECT customer# FROM customersJOIN orders USING(customer#)WHERE shipdate-orderdate IN(SELECT MAX(shipdate-orderdate) FROM ordersWHERE shipdate IS NULL);a. The SELECT statement fails and returns an Oracle error message.b. The outer query displays no rows in its results because the subquery passes a NULLvalue to the outer query.c. The customer number is displayed for customers whose orders haven’t yet shipped.d. The customer numbers of all customers who haven’t placed an order are displayedThe Driver Relationship team realized that maintaining driver IDs is difficult and requested an automatic way of incrementing the value when a new driver is added. You need to make the changes on the table to automatically increment the Driver ID. After the change, you need to insert the following driver: First Name: Nursin Last Name: Yilmaz Driving License ID: 4141447 Start Date: 2019-12-28 Driving License Checked: True Rating: 4.0 THIS IS IN SQL FORMAT FOR CENGAGE MINDTAP, PLEASE HELP I AM STUCK
