5. Solve the differential equation for the given initial conditions. d'r 4- dt2 dr dr +4 +37x = 0, r(0) = 0, (0): = 2. %3D dt dt Explain what the solution of this equation represents.

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A: We rewrite the differential equation as dydx=4y. Now dy4y=dx⇒∫dy4y=∫dx⇒14∫dyy=∫dx⇒14 ln y=x+C1⇒ln…

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A: given,             y'=2y       and y(0) = 2

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A: Given : y' = yy0 = 4

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A: This is Separable differential equation

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A: Answer is in below step.

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