5. The nucleus of atom spontaneously divides into three fragment nuclei with masses m, 2m and 5m. The velocities of the first two fragments are perpendicular to eath other and equal 3v and 2v. The speed of the third fragment 1). v 2). 2v 3). Зv 4). 4v 6. A body of m, moving at v along a smooth horizontal surface, collide with a horizontally spring with a spring constant k (see figure). The maximum compress value Al for the spring 1). Al = v k 2). Al = v 3) Al = vvmk 4) Al = v/Vmk %3D ||

icon
Related questions
Question
5. The nucleus of atom spontaneously divides into three fragment nuclei with masses m,
2m and 5m. The velocities of the first two fragments are perpendicular to eath other and
equal 3v and 2v. The speed of the third fragment
1). v
2). 2v
3). Зv
4). 4v
6. A body of m, moving at v along a smooth horizontal surface, collide with a
horizontally spring with a spring constant k (see figure). The
maximum compress value Al for the spring
1). Al = v
k
2). Al = v
3) Al = vvmk
4) Al = v/Vmk
%3D
||
Transcribed Image Text:5. The nucleus of atom spontaneously divides into three fragment nuclei with masses m, 2m and 5m. The velocities of the first two fragments are perpendicular to eath other and equal 3v and 2v. The speed of the third fragment 1). v 2). 2v 3). Зv 4). 4v 6. A body of m, moving at v along a smooth horizontal surface, collide with a horizontally spring with a spring constant k (see figure). The maximum compress value Al for the spring 1). Al = v k 2). Al = v 3) Al = vvmk 4) Al = v/Vmk %3D ||
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer