5. Theory: Archimedes' Principle: The buoyant force on an object equals the weight of the fluid it displaces. In equation form, Archimedes' principle is FB = Wfl, where FB is the buoyant force and wfi is the weight of the fluid. Problem: Calculate the buoyant force on 10000 metric tons or 1.0 x 107 kg of solid steel completely submerged in water, and compare this with the steel's weight. Given, steel's density is 7.8 x 10³ kg/m³. (b) What is the maximum buoyant force that water could exert on this same steel if it were shaped into a boat that could displace 1.0 x 105 cubic met water? (this is a solved problem in the textbook, see Chapter 11.7 Archimedes' Principle)

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5. Theory: Archimedes' Principle: The
buoyant force on an object equals the
weight of the fluid it displaces. In
equation form, Archimedes' principle is
FB = Wfl, where FB is the buoyant force
and wfi is the weight of the fluid.
Problem: Calculate the buoyant force on
10000 metric tons or 1.0 x 107 kg of solid
steel completely submerged in water,
and compare this with the steel's weight.
Given, steel's density is 7.8 x 10³ kg/m³.
(b) What is the maximum buoyant force
that water could exert on this same steel
if it were shaped into a boat that could
displace 1.0 x 105 cubic met water? (this
is a solved problem in the textbook, see
Chapter 11.7 Archimedes' Principle)
Transcribed Image Text:5. Theory: Archimedes' Principle: The buoyant force on an object equals the weight of the fluid it displaces. In equation form, Archimedes' principle is FB = Wfl, where FB is the buoyant force and wfi is the weight of the fluid. Problem: Calculate the buoyant force on 10000 metric tons or 1.0 x 107 kg of solid steel completely submerged in water, and compare this with the steel's weight. Given, steel's density is 7.8 x 10³ kg/m³. (b) What is the maximum buoyant force that water could exert on this same steel if it were shaped into a boat that could displace 1.0 x 105 cubic met water? (this is a solved problem in the textbook, see Chapter 11.7 Archimedes' Principle)
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