5. Write all the characters associated with the ASCII values 48 to 57.
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- the odd numbers are the numbers in the sequence 1,3,5,7,9, .... Define the sequence of S - numbers as follows: the first S - number is 1 The second S - number is the sum of the first S - number and the second odd number the third s - number is the sum of the second S- number and the third odd number. the fourth S- number is the sum of the third S- number and the fourth odd number, etc..,... compute the first seven S- numbers. make a note of any patterns you notice. enter the first seven S- numbers as a comma - seperated list: first seven S- numbers = ________________1. Using only the code below (do not modify), find the one of the roots of the quadratic formula. Thanks experts!4. ~(~C ≡ ~A) ѵ [(B ѵ C) • X] a) Replace each statement with the given assigned truth-values and rewrite the problem with the assigned truth-values ~(~t ≡ ~t) ѵ [(t ѵ t) • f] b) Using the truth-table, solve for the truth-value of the compound statement
- 44. What is the value of the following expression:24//6%3, 24//4//2 a. (1,3) b. (0,3) c. (1,0) d. (3,1)Use C++ A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.bool IsLeapYear(int userYear)fill in the blanks in the code
- 11.4.1: Leap year - functions. A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. If the input is 1712, the output is: 1712 is a leap year. If the input is 1913, the output is: 1913 is not a leap year. Your program must define and call a function: Function OutputLeapYear(integer inputYear) returns nothing The function should output whether the input year is a leap year or not. Need program written in the coral language51. What is the result of the snippet of code shown below if x=1?x<<2 a. 8 b. 1 c. 2 d. 43.22 LAB: Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.
- C++ What does the following segment of code output to the screen (be precise)? #include <iostream> using namespace std; int main() { int number1 = 2; int number2 = 4; if (number1 == number2) cout << number1 << " == " << number2 << endl; if (number1 != number2) cout << number1 << " != " << number2 << endl; if (number1 < number2) cout << number1 << " < " << number2 << endl; if (number1 > number2) cout << number1 << " > " << number2 << endl; if (number1 <= number2) cout << number1 << " <= " << number2 << endl; if (number2 >= number1) cout << number1 << " >= " << number2 << endl; cout << "number1 is " << number1 << " number2 is " <<…C CODE 3.22 LAB: Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.Let A = {a, b, c} and B = {u, v}. Write a. A × B b. B × A