5.1 For the circuit in the image below, if R1 = 11 kN and R2 = 6 kN, determine the gnitude of the current (in mA) that flows through the 20-k2 resistor. %3D mA (4 R, Vo 0.01V. R2 20 k2 ase pay attention: the numbers may change since they are randomized. Your swer must include 1 place after the decimal point. ur Answer: Answer
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- Kirchoff's Law Problem Find the direction and the equation will be used. Also find the i's, Vr1 to Vr7 and P1 to P7. Given: Use the following given for batteries and resistors (color bands for your value of resistors, use the lower limit). R1 = red red blue black goldR2 = orange green black silverR3 = white orange orange black goldR4 = green white violet black goldR5 = violet blue red black silverR6 = yellow green blue black silverR7 = brown black black black gold V1 (lower left) = 100VV2 (top) = 150VV3 (lower right) = 200V Thank you!For the solution provided, i do not understand, when finding w = infinity, why do we take into account the imaginary numbers only (R2 /(R1+R2))? Pls provide the derivation of the formula as shown in the solutionVbatt=25 VC1=90 ?CC2=75 ?CC3=60 ?CR1=160 ΩR2=120 Ωt2=21.6 msect3=27 msecConsider the circuit shown below which shows a battery connected to some resistors and capacitors along with some switches which will be toggled opened or closed at different times. The components are listed above. The capacitances are in microFarads (?F), the resitances are in Ohms (Ω), and the times are in milliseconds (msec). A stopwatch is started at time t1=0 ms. At that time, switch S1 is closed and all other switches are open and the capacitor is allowed to charge up.(a). (i)What is the charge (in uC) on C1 at the time the stopwatch reads t2=21.6 ms?a)3690 b)1520 c)5710 d)2630 e)683 f)1750 (a).(ii)What is the current (in mA) through R1 at t2=21.6 ms?34.9 30.4 114 13.6 73.6 52.4 (b)(i)What is the voltage (in V) across R1 at t2=21.6 ms?8.37 5.58 2.18 11.8 18.2 4.85(ii). What is the voltage (in V) across C1 at t2=21.6 ms?63.2 29.1 40.9 7.57 19.4 16.9(c). (i) What is the energy (in mJ) in C1 at t2=21.6 ms?6.63…
- Vbatt=25 VC1=90 ?CC2=75 ?CC3=60 ?CR1=160 ΩR2=120 Ωt2=21.6 msect3=27 msecConsider the circuit shown below which shows a battery connected to some resistors and capacitors along with some switches which will be toggled opened or closed at different times. The components are listed above. The capacitances are in microCoulombs (?C), the resitances are in Ohms (Ω), and the times are in milliseconds (msec). A stopwatch is started at time t1=0 ms. At that time, switch S1 is closed and all other switches are open and the capacitor is allowed to charge up.(a). What is the charge (in uC) on C1 at the time the stopwatch reads t2=21.6 ms?Ans: 1750 uC(b). What is the current (in mA) through R1 at t2=21.6 ms?Ans: 34.9 mA(c). What is the voltage (in V) across R1 at t2=21.6 ms?Ans: 5.58 V(d). What is the voltage (in V) across C1 at t2=21.6 ms?Ans: 19.4 V(e). What is the energy (in mJ) in C1 at t2=21.6 ms?Ans: 17.0 mJThen, immediately at time t2=21.6 on the stopwatch, switch S1 is thrown open and…Lightbulbs are rated by their power consumption in watts (W). Electricity is sold in units of energy, which is power multiplied by time. Electricity costs vary widely across the United States and are on the order of 0.08–0.30 $/kW-hr for residential customers. Create a spreadsheet that utilizes electricity costs and the number of hours per day that a lightbulb is on as input variables. Then calculate the annual cost to operate a 60-W, 75-W, and 100-W incandescent bulb and the equivalent LED bulbs consuming 8, 10, and 16 W, respectively. Assuming the average household operates six 60-W, four 75-W, and two 100-W incandescent bulbs for 6 hours a day, how much money can they save in a year by changing all the bulbs to equivalent LED bulbs?Bioelectrical impedance analysis is a commercially available method used to estimate body fat percentage. The device applies a small potential between two parts of the patient's body and measures the current that flows through. With an estimate of the resistance individually of the muscle and fat between the two points, the composition of the tissue can be estimated. Assume that the muscle and fat tissue can be modeled as resistors in parallel. a) If a potential difference of 5 V is applied across the patient's arm, what is the potential drop across the patient's fat? b) If the measured resistance of the patient's arm is 750 Ω and the resistance of fat is 3 times that of muscle, what is the resistance of the muscle?
- Ohm's law gives the relationship between voltage, resistance, and current in a simple circuit: V = IR. a) Find (dV/dt) in terms of I, R, (dI/dt) and (dR/dt). Assume all quantities are functions of time. b) We have a circuit with 500 Ω resistor, and we ramp up the voltage. How quickly is the current changing when we are increasing the voltage by 10 V/s? It will help to remember that t is the independant variable here. Include units, note that 1Ω = 1V/A. c) Is the current increasing or decreasing? How can you tell? *PLEASE SOLVE ONLY PART B and CA container equipped with a resistance heater and a mixer is initially filled with 3.6 kg of saturated water vapor at 120°C. Now the heater and the mixer are turned on; the steam is compressed, and there is heat loss to the surrounding air. At the end of the process, the temperature and pressure of steam in the container are measured to be 300°C and 0.5 MPa. The net energy transfer to the steam during this process isYou are designing a new eco-friendly thermal coffee mug. It is shaped like a small globe to minimize surface area, which is only about 0.04m^2. You use two 0.003m layers of recyclable PETE which has a thermal conductivity, k, of 0.2W/mK around a 0.01m layer of dead air, with a thermal conductivity of 0.026W/mK. Since this is for hot coffee, use a temperature difference of 40K. Q = Ax (T2-T1) / (R1 + R2 + etc) R =x/k. What is the R-value for each of the two PETE layers
- What are the primary dimensions of electric voltage (E)? (Hint: Make use of the fact that electric power is equal to voltage times current.) When performing a dimensional analysis, one of the first steps is to list the primary dimensions of each relevant parameter. It is handy to have a table of parameters and their primary dimensions. We have started such a table for you in which we have included some of the basic parameters commonly encountered in fluid mechanics.add to this table. You should be able to build up a table with dozens of parametersA battery of emf 30.0 V is connected to a switch, an inductor of inductance ? = 0.600 ? and two resistors, R1 = 10.0 ? and R2 = 6.00?. The switch is initially open. A. What are the values of currents ?1, ?2, ?3 just after the switch is closed? (Just give an answer) ?1 = ?2 = ?3 = B.)Which point, a or b, is at higher potential or are they at the same potential, just after switch S is closed? (Just give an answer) C. What is the value of current ?1 through the battery a long time after the switch is closed? Show your work and briefly explain your logicAs shown, the battery has emf ε = 18.0 V and the other circuit elements have values L = 0.400 H, R1 = 2.00 kΩ, and R2 = 6.00 kΩ. The switch is closed for t < 0, and steady-state conditions are established. The switch is then opened at t = 0. (a) Find the emf across L immediately after t = 0. (b) Which end of the coil, a or b, is at the higher potential? (c) Make graphs of the currents in R1 and in R2 as a function of time, treating the steady-state directions as positive. Show values before and after t = 0. (d) At what moment after t = 0 does the current in R2 have the value 2.00 mA?