5.14 Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ¹/2 ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate: Trial 1 = 76.6 lb Trial 2 = 75.1 lb Questions and Problems 217 Trial 3 = 78.8 lb a. Calculate the average dry-rodded unit weight

5.14 Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ¹/2 ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate: Trial 1 = 76.6 lb Trial 2 = 75.1 lb Questions and Problems 217 Trial 3 = 78.8 lb a. Calculate the average dry-rodded unit weight

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket ½ ft3 Weight of empty bucket Weight of bucket filled with dry rodded coarse aggregate 20.3 lb Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ½ ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 0.3 cuft Weight of empty bucket is 18.1 lb Weight of bucket filled with dry rodded coarse aggregate = 58.7 lb Calculate the dry-rodded unit weight in lb/ft^3 (one decimal only). Input magnitude only.
Problem 1: ProCoarse aggregate is placed in a rigid bucketand rodded with a tamping rod to determine itsunit weight. The following data are obtained: Volume of bucket = 1/3cuftWeight of empty bucket is 18.5 lbWeight of bucket filled with dry rodded coarse aggregate = 55.9lb a. Calculate the dry-rodded unit weightb. If the bulk dry specific gravity of theaggregate is 2.63, calculate the percent voids inthe aggregate.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: (Note: Write answer with 2 decimal places) Volume of bucket = 1/2 cu.ft Weight of empty bucket = 20.3 Ib Weight of bucket filled with dry rodded coarse aggregate: Trial 1 = 76.6 Ib Trial 2 = 75.1 Ib Trial 3 = 78.8 Ib a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial. {Note: Bulk Dry specific gravity must be multiplied to the unit weight of water to obtain percent voids)
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kg Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.
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Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 0.481 %3D Weight of empty bucket = 22.107 Ib %3! Weight of bucket filled with dry rodded coarse aggregate Trial 1 = 69.259 lb %3D Trial 2 = 70.567 lb Trial 3 = 69.708 lb • If the bulk dry specific gravity of the aggregate is 2.727, calculate the percent voids for trial 2. where unit weight of water is 62.40
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 1/3 ft3Weight of empty bucket = 18.5 lbWeight of bucket filled with dry rodded coarse aggregate = 55.9 lba. Calculate the dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.630, calculate the percent voids in the aggregate.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry- %3D rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kgMeasureSampleA B CWet Mass (g) 521.0 522.4 523.4Dry Mass (g) 491.6 491.7 492.1Absorption (%) 2.5 2.4 2.3Table P 5 . 9 determine the amount of water required to increase the moisture content of aggregate to reach absorption?5.9 Three samples of fine aggregate have the properties shown in Table Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.