5.25V pp RS y2 P = R A voltage is applied to a resistor of 180ohm. The voltage can be: (1) AC sinewave of 1kHz and 5.25Vpp, (2) AC rectangle of 2kHz and 5.25Vpp, (3) DC voltage of 5.25V. The highest power dissipated by the resistor is achieved for: The AC sinewave voltage, since the Vrms is greater than the rectangle and the DC voltage. The answer cannot be determined, since we cannot compare the power dissipated by a resistor connected to AC and DC voltages. The DC voltage, since the effective value is higher than compared to the other two voltages. The power is the same for all 3 cases, since the value of the voltage is the same. The AC rectangle voltage, since the Vrms is greater than the sinewave and the DC voltage. The DC voltage, since the others are AC and the average value is 0. hp

5.25V pp RS y2 P = R A voltage is applied to a resistor of 180ohm. The voltage can be: (1) AC sinewave of 1kHz and 5.25Vpp, (2) AC rectangle of 2kHz and 5.25Vpp, (3) DC voltage of 5.25V. The highest power dissipated by the resistor is achieved for: The AC sinewave voltage, since the Vrms is greater than the rectangle and the DC voltage. The answer cannot be determined, since we cannot compare the power dissipated by a resistor connected to AC and DC voltages. The DC voltage, since the effective value is higher than compared to the other two voltages. The power is the same for all 3 cases, since the value of the voltage is the same. The AC rectangle voltage, since the Vrms is greater than the sinewave and the DC voltage. The DC voltage, since the others are AC and the average value is 0. hp

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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