Please solve showing steps. I am told that the given answer is off by a few hundred pounds. 5.3. What is the maximum force developed in a cable carrying a uniform load of 500 lb/ftthat spans 200 ft? Assume that the cable has a maximum midspan sag of 20 ft.Answer: 135,000 lb

The maximum force in the cable is 134629.12 lb.Explanation:Step 1:Step 2:

Answered: 5.3. What is the maximum force…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A cable whose length is 16m and sag of 2m supports a weight of 1500 N/m. If the allowable tension in the cable is 35 KN, what is the maximum value of w?
A cable supports 100-KN load at point B and 80-KN load at point C as shown in the figure. Determine yB and the tensions in segments AB, BC and CD of the cable.
Since the greatest sag in the cable given in the figure is h = 3.5 m, calculate the maximum cable strength with the A and B support reactions.
The parabolic cable shown carries a uniform load of 70 kN/m. The lowest point of the cable is located vertically 8 meters from the left support and 19 meters from the right support. If the length of the cable is 110 meters, determine the value of the maximum tensile force (kN) that the cable can withstand.
What is the maximum tension (approximately) in the cable as shown in figure, if it carries a uniform horizontally distributed load of intensity 120 kN/m?
Answer is 9,872.198 kN. Please show solution. The parabolic cable shown carries a uniform load of 70 kN/m. The lowest point of the cable is located vertically 7 meters from the left support and 19 meters from the right support. If the length of the cable is 110 meters, determine the value of the maximum tensile force (kN) that the cable can withstand.
3. The parabolic cable shown carries a uniform load of 80 kN/m. The lowest point of the cable is located vertically 6 meters from the left support and 17 meters from the right support. If the length of the cable is 80 meters, determine the value of the maximum tensile force (kN) that the cable can withstand. Round off to three decimal places.
Determine the maximum uniform loading w, measured in lb/ft, that the cable can support if it can sustain a maximum tension of 3000 lb before it will break.
A 150-lb wrecking ball B is attached to a 40-ft-long steel cable AB and swings in the vertical arc shown. Determine the tension in lb f of the cable at the bottom D of the swing, where the speed of B is 13.2 ft / s .
A cable supports a load of 50 kg/m uniformly distributed along the horizontal and is suspended from the two fixed points A and B located as shown. a. Calculate the cable tensions at A and B. b. Determine the length of the cable.
Calculate the span and sag of a cable 600ft. long weighing 3 lb/ft and supported at points on the same level with a maximum tension of 1800lb.
7 Given the Cable as shown below that weighs 15 N/m with the tensile force at Point B that is found to be 500 N.Determine the following:a.) The Tension at Point A.b.) The Minimum Tension in the Cable.c.) The Span of the Cable L.

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5.3. What is the maximum force developed in a cable carrying a uniform load of 500 lb/ft that spans 200 ft? Assume that the cable has a maximum midspan sag of 20 ft. Answer: 135,000 lb