59: For the beam in Fig. P5.9, determine the extreme value of the shearing force and bending moment at point D due to the concentrated live load of 30 kN, a unifomly distributed live load of 3 kN/m (of any length), and a uniformly distributed dead load of 1 kN/m.
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- Determine the reaction forces R1 and R2 and show the shear and bending moment diagram. Data: Point load (left-most) = 90.126 N RL1 (80mm to 160mm) = 65 N RL2 (160mm to 180mm) = 130 N RL3 (180mm to 260mm) = 65 NDetermine the member end moments and reactions for the continuous beam shown in the Figure (a) due to the uniformly distributed load and due to the support settlements of 10 mm at A, 50 mm at B, 20 mm at C, and 40 mm at D. Use the three-moment equation. Ans. MB =115.2 kN.m , MC = 451.2 kN.m, Ay = 138.5 kN, By = 277.9 kN, Cy = 378.7 kN, Dy = 104.9 kNDetermine the maximum ultimate positive and negative moments for the simply supported beam withan overhang under different loading patterns of live load combined with dead load. Also draw the shearand moment diagrams and calculate the location of the point of inflection. WD = 20 KN/m (including selfweight), WL = 30 KN/m.
- 3. The Shear diagram of a loaded beam is shown in the Fig. Which of the following gives the largest concentrated load (not include the reaction) acting on the beam in Kilonewton? Which of the following gives the maximum negative bending moment in Kilonewton-meter? Which of the following most nearly gives the location of a point of inflection moment) form the right end of the beam in meters?For the beam shown in figure below, draw the shear and moment diagrams: 1- Due to applied loads (without support settlement). 2- Due to support settlement of 60 mm downward at support B (without loads). Take the stiffness El as 12000 kN.m?. 50 kN SKN/mCompute for the Beam Reactions and draw the Shear and Moment Diagram of the beam using Moment Distribution Method (MDM) Only. Assume EI = 20000 kNm^2 to compute for FEM Find the relative stiffness
- A 10-meter long simply supported beam carries a uniform load of 8 KN/m for 6meters from the left support and a concentrated load of 15 KN 2 meters from the right support. Determine the maximum shear and moment.Determine the max positive shear that can be developed at point C in the beam due to concentrated moving load of 4000lb and a uniform moving load of 2500lb/ftFor the frame and loadings shown P=2240 KN, and F=1120 magnitude of verticalreaction at E magnitude of verticalreaction at A magnitude of verticalreaction at C
- A 10-meter-long simply supported beam is carrying a concentrated load of magnitude 8 kN at its midspan and a uniformly distributed load of 4 kN/m from its roller support to a point 3m from its pin support. 1. Solve for the internal shear and moment developed at the midspan due to the given loads.2. Express the internal shear and moment of the beam as function/s of x.1. A simply supported beam has a length of 6 meters. If a super imposed concentric load of 50 kN was placed 2 meters away from the left support A what should be the shear reaction at support A? a. 33.33 kN b. 44.44 kN c. 16.67 kN d. 50.33 kN 2. What is the reaction at support B of question 1? a. 50.33 kN b. 44.33 kN c. 33.33 kN d. 16.67 kNFor the section shown in Fig.1 if the applied moment =200 KN.m, n=12, b =841 mm, d=500 mm, As =1814 mm2, bw=250 mm, and hf =106mm. Find compression force C1 in terms of fc