5х + 2у — — 1 4х — Зу — 2 14 1 y = x = 23 23 1 14 23' Y = 23 x = 14 1 x = 23 23 14 1 y = 23 23

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.2: Direct Methods For Solving Linear Systems
Problem 3AEXP
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Solve the following system of equations.
5а + 2у — — 1
4х — Зу — 2
1
14
23
23
14
1: = -
23
23
1
14
23
23
14
1
x =
23
23
Transcribed Image Text:Solve the following system of equations. 5а + 2у — — 1 4х — Зу — 2 1 14 23 23 14 1: = - 23 23 1 14 23 23 14 1 x = 23 23
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