6-1.2-1: Find lightest W14 for L = 20', P = 600k E = 29,000ksi, Fb = 30ksi and Fv = 20ksi. 30. CONTINUOUS BEAM-TWO EQUAL SPANS-CONCENTRATED LOAD AT CENTER OF ONE SPAN Total Equiv. Uniform Load 13 p 8 P 2 R,= V₁.. 32 R R₂ R₁ R₂= V₁ + V₂. 11 p 16 V₁ R= V₁. V₂ Mmax (at point of load). M. (at support R)..... .......... Amax (at 0.480 / from R.).... M Inax Shear Moment M₁ V₂ ********** ********** 11 = 11 P 11 32 19 p 32 = 3. Pl 13 64 = PI 32 0.015 P³ El
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- The rectangular beam with a span length of 7.2 m has an effective depth, d = 430mm and a width of 250mm. It has 2-legged 10mmØ stirrups spaced at 130 mm on centers all throughout the beam length. Determine the maximum wu that the beam can carry based on the shear capacity of the beam. Use fc' = 21MPa and Grade 40 rebars. a. Adopt smaller of S' : S'1 = Avfy / (0.062b√f'c) S'2 = Avfy / (0.35b) b. S" = (0.062/0.33) / S'1 c. 1. if S > S' ; ØVn = Ø 0.5Vc 2. if S"<S<S' ; Smax = least of S' or d/2 or 600mm i. S> Smax ; ØVn = Ø 0.5Vc ii. S< Smax ; ØVn = Ø (Vc + ( Avfyd / S ) ) 3. if S < S" ; Smax = least of S' or d/4 or 300mm i. S> Smax ; Vs = 0.33√f'c bwd ØVn = Ø (Vc + 0.33√f'c bwd) ii. S< Smax ; ØVn = Ø (Vc + ( Avfyd / S ) ) Find: 1. Vc 2. s' and s'' 3. smax 4. ØVn 5. Wu34 - A support is a fixed, B support is a sliding joint. loads M= 30 kNm, P1= 12 kN, P2= 13 kN, q1= 6 kN ⁄ m, q2= 7 kN ⁄ m , spans are a= 2 m, b= 3 m. The support reactions in the beam whose loading condition is given in the figure will be found. Accordingly, Ax = ?A) 22.25B) 0C) None.D) 39.25E) 21/2BAL=8 mt = 13 mm-150 mm113 mmFor the steel column with both ends fixed against rotation having a tubularcross-section, determine the allowable load Pall against buckling. E=200 GPa andOy=250 MPa.
- A T-beam (internal) for a floor system has a slab thickness of 100mm and a total depth of 550mm. It hasa web thickness of 300mm. The T-beam is casted monolithically with the slab. The beam has a simple spanof 6.0m with a spacing of 2.4m center to center. The beam carries a live load moment of 163 kN.m and adead load moment of 84 kN.m. Assume f’c = 20.7 MPa and fy = 413.7 MPa. Assume steel covering to thecentroid of the reinforcement is 65mm. Determine the following and discuss your solution:(a) Effective width of flange(b) Depth of compression block(c) Steel area requiredSteel Design Two channels having the given properties shown is placed at a distance of 300 mm to back and is properly connected by a pair of lacings as shown. Properties of one channel A = 5595 mm2 d = 305 mm x = 17mm Ix = 67.3 x 106 mm4 Iy = 2.12 x 106 mm4 rx = 19.3 mm Assume K = 1.0 Determine the safe axial load in kN, that the column section could carry. Unsupported height of column is 6m.A cantilever beam of 7.4—ft(2.20—m) span carries a uniform dead load of 685 Ib/ft(10kN/m) and a concentrated live load of 18k (80 kN) at a distance 3ft(0.9m) from the face of the support. design the beam for moment and shear using the strength design method. given: f’c=3ksi (21 MPa), fy=60 ksi (420 MPa), b=8in. (200mm) and use p=3/4pmax
- 14. A short rectangular column 300 mm on one side and 400 mm on the other side. It is reinforced with 8-20-mm-diameter (28) longitudinal bars equally distributed to the shorter sides of the column. Use f’c = 21 MPa and fy = 415 MPa. 46. Calculate the required spacing of 10-mm-diameter ties. s = ____ mm 47. Calculate the nominal axial strength of the column in, Pn = _____ kN. (rounded to the nearest whole number) 48. Calculate the maximum ultimate axial load the column can carry, Pu = _____kN. (rounded to the nearest whole number)A short rectangular column 300 mm on one side and 400 mm on the other side. It is reinforced with 8-20-mm-diameter (28) longhitudinal bars equally distributed to the shorte sides of the column. Use f'c = 21 MPa and fy = 415 MPa. Calculate the required spacing of 10-mm-diameter ties, s (mm). Calculate the nominal axial strength of the column, Pn (kN). Calculate the maximum ultimate axial load the column can carry, Pu (kN)An exterior T-beam has a clear simply supported length of 6.75m. It has a clear distance to the next webof 3.5m. The base of the web to the beam is 350mm and has an effective depth of 500mm. Use 4-28mm diameter reinforcements with a slab thickness of 120 mm. f'c = 21 Mpa ; fy = 415 Mpa. a. effective width of the flange b. depth of compression block of the beam c. total area of the compression block d. ultimate moment capacity of the beam
- For the given loads F1=42 KN, F2=48 KN, F3=45 KN, F4=32 KN (Assume internal forces are in tension) 1- Magnitude of reaction at K is (KN) :(a. 151 - b. 226.5 - c. 302 - d. 377.5 - e. 453 ) 2- internal force in member JH (KN) :(a. -327 - b. -218 - c. -436 - d. -545 - e. -654) 3- internal force in member IH (KN) : (a. -204.600222 - b. -136.400148 - c. -272.800296 - d. -341.00037 - e. -409.200444 ) 4- Magnitude of reaction at A is (KN) 5- internal force in member IK (KN) is 6- internal force in member GF (KN)A 4.0 m rectangular cantilever beam is loaded with ultimate uniform load Wu=45kN/m over the whole span and concentrated load Pu= 70kN at the free end. Using As=6-25mm, b=250mm, h=400mm, f'c=21MPa, fy=276MPa, cc=50mm, and stirrups=10mm, determine the following: Determine the effective depth of the beam in mm.0 Determine the critical shear Vu in kN.0 Determine the load to be carried by the stirrups Vs in kN.0 show clear solution thank youA 4.0 m rectangular cantilever beam is loaded with ultimate uniform load Wu=45kN/m over the whole span and concentrated load Pu= 70kN at the free end. Using As=6-25mm, b=250mm, h=400mm, f'c=21MPa, fy=276MPa, cc=50mm, and stirrups=10mm, determine the following: Determine the effective depth of the beam in mm.0 Determine the critical shear Vu in kN.0 Determine the load to be carried by the stirrups Vs in kN.0